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I started with a=1 and b=2 and so c^2=1^2-2^2 it ends up to be c^2=-3 but i don't feel as that's right
Look at the graph, we can see that the foci must be on the x-axis, hence, the coordinate must be under the form of (-x,0) and (x,0). Therefore, we can get rid of A and D
Now, if it is B, the point \((1+\sqrt 3,0)\) has x-coordinate >1, that is it is out of the graph --> cannot be a foci. Now, we have just.......??
@Loser66 just C left
Yup, but does it make sense to you?
@Loser66 yeah i'll look at this next time i'm having trouble
do you know what is special about the foci
@dan815 Yes, I do. However, in this case, it is easier than the traditional way on finding the foci out by rejecting the wrong one.
if you draw a straight line from one foci to another foci while hitting the ellipse anywhere once, the length of the lines forces is constant, using that we can figure out where a foci is for any ellipsode with a and b, dominant and codominant axis respectively