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anonymous
 one year ago
find an equation for the nth term of a geometric sequence where the second and fifth terms are 21 and 567, respectively.
an = 7 (3)n^( + 1)
an = 7 3^(n  1)
an = 7 (3)^(n  1)
an = 7 3^n
anonymous
 one year ago
find an equation for the nth term of a geometric sequence where the second and fifth terms are 21 and 567, respectively. an = 7 (3)n^( + 1) an = 7 3^(n  1) an = 7 (3)^(n  1) an = 7 3^n

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[a _{n}=ar ^{n1^{}}\] \[find~a _{2}~and~a _{5}\] and divide

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0let a be the first term find a2 and a5

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[a _{2}=ar ^{21}=ar=21\] \[a _{5}=ar ^{51}=ar^4=567\] divide \[\frac{ ar^4 }{ ar }=\frac{ 567 }{ 21 },r^3=27=\left( 3 \right)^3,r=3\] ar=21 find a

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{ ar }{ r }=\frac{ 21 }{ 3 }=?\] then write an=?

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.0if 2nd term is negative and 5th term is positive, then the common ratio is obviously negative. ((There is no other way for such geom. sequence))

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@SolomonZelman its c right?
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