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anonymous
 one year ago
A system of equations is shown below:
6x – 2y = 3 (equation 1)
5x + 3y = 4 (equation 2)
A student wants to prove that if equation 2 is kept unchanged and equation 1 is replaced with the sum of equation 1 and a multiple of equation 2, the solution to the new system of equations is the same as the solution to the original system of equations. If equation 2 is multiplied by 1, which of the following steps should the student use for the proof?
anonymous
 one year ago
A system of equations is shown below: 6x – 2y = 3 (equation 1) 5x + 3y = 4 (equation 2) A student wants to prove that if equation 2 is kept unchanged and equation 1 is replaced with the sum of equation 1 and a multiple of equation 2, the solution to the new system of equations is the same as the solution to the original system of equations. If equation 2 is multiplied by 1, which of the following steps should the student use for the proof?

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misssunshinexxoxo
 one year ago
Best ResponseYou've already chosen the best response.1Ok please stop spamming the question kamui

misssunshinexxoxo
 one year ago
Best ResponseYou've already chosen the best response.1Hello; are you familiarized on how to solve system of equations?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Gee thanks man! I'm totally going to pass this test. @kamuigakupo And no not really @misssunshinexxoxo

misssunshinexxoxo
 one year ago
Best ResponseYou've already chosen the best response.111x + y = 7 and 5x + 3y = 4 is the same as the solution to the given system of equations

misssunshinexxoxo
 one year ago
Best ResponseYou've already chosen the best response.1That is your answer

misssunshinexxoxo
 one year ago
Best ResponseYou've already chosen the best response.111x+y=7 6x2y=3 5x+3y=4

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Oh I see! Thanks! Do you think you can help me with another?

misssunshinexxoxo
 one year ago
Best ResponseYou've already chosen the best response.1Please close this question and make a new one tag me:)
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