## anonymous one year ago Any one wanna help with some alg 2 questions? fan and medal

1. anonymous

@dan815 @ganeshie8 @texaschic101 @rockstar0765 @paki

2. pooja195

What 2 questions?

3. anonymous

What is the solution of log4x − 1032 = 5? and its Algebra 2 like the subject lol @pooja195

4. Owlcoffee

You'll have to apply logarithmic properties n order to make that simpler.

5. anonymous

yeah i dont remember how to and i was wondering if someone would walk through it with me

6. sweetburger

alright is that the logbase 4 of x? or log base 10 of 4x

7. anonymous

i feel like its log base 4 cause thats exactly how it was written

8. sweetburger

sorry its just hard to tell on the computer :/

9. anonymous

its fine!

10. sweetburger

alright if it is log base 4 of x then we could say that 4^1037=x which seems very strange

11. sweetburger

that number is going to be massive

12. anonymous

yeah it seems massive already lol

13. anonymous

where did 1037 come from though?

14. sweetburger

1032+5 = 1037 i just moved the 1032 to the otherside

15. anonymous

oh okay i gotcha

16. anonymous

wouldnt it be -1032 +5?

17. sweetburger

alright so the equation says log4x -5=1032 so I added 5 to both sides so it became log4x = 1037. Also could u possible take a screenshot or pictures of the question because i feel like its not being expressed correctly the way it is written.

18. anonymous

nononono the equation is log4x-1032=5

19. ybarrap

It's more likely that the problem is $$\Large { \ln^4x=5+1032=1037\\ \ln x=\sqrt[4]{1037}\\ x=\exp^{\sqrt[4]{1037}} }$$ Which is, not so massive. http://www.wolframalpha.com/input/?i=%281037%29%5E%281%2F4%29