## vera_ewing one year ago How does adding NH3 to the reaction below affect the equilibrium of the reaction? N2(g) + 3H2(g) 2NH3(g) A. Increasing the amount of NH3 will make Q smaller than K. A net reaction occurs in the direction to increase NH3, or the forward reaction. B. Increasing the amount of NH3 will make Q smaller than K. A net reaction occurs in the direction to reduce NH3, or the reverse reaction. C. Increasing the amount of NH3 will make Q larger than K. A net reaction occurs in the direction to increase NH3, or the forward reaction. D. Increasing the amount of NH3 will make Q larger th

1. vera_ewing

@sweetburger A or B?

2. sweetburger

Does D say that Increasing the amount of NH3 will make Q larger than K. A net reaction occurs in the direction to reduce NH3, or the reverse reaction. ?

3. vera_ewing

Increasing the amount of NH3 will make Q larger than K. A net reaction occurs in the direction to reduce NH3, or the reverse reaction.

4. sweetburger

Pretty sure it is D. As q represents the initial reaction quotient. If the reaction quotient has the amount of products increased which is the numerator it will become larger than the K value. To get Q to become K a reverse reaction must occur.

5. vera_ewing

Yeah you're right. Thank you.

6. vera_ewing

7. vera_ewing

8. sweetburger

i think you just take the square root of the solubility

9. vera_ewing

So D?

10. sweetburger

No, I believe it would be B.

11. sweetburger

i said that [Ag+][I-]=8.5x10^-17 then i let Ag and I represent x xo [x][x]=8.5x1-^-17 so $\sqrt{8.5x10^-17} =9.2x10^-9$

12. sweetburger

so x= 9.2x10^-9

13. vera_ewing

Ohh I see. Thanks for explaining that!