• anonymous
For the reaction shown, calculate how many grams of oxygen form when each quantity of reactant completely reacts. 2 KClO3(s) → 2 KCl(s) + 3 O2(g) 2.72 g KClO3 0.361 g KClO3 83.6 kg KClO3 22.5 mg KClO3
  • Stacey Warren - Expert
Hey! We 've verified this expert answer for you, click below to unlock the details :)
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
  • jamiebookeater
I got my questions answered at in under 10 minutes. Go to now for free help!
  • Photon336
2KClO3(s) --> 2KCl(s) + 3O2 assuming the reaction goes to completion: given 2.72grams of KCLO3 covert this to moles: so it would be 2.72g x (1mol/123g) notice grams cancel out and you're left with moles. then you get roughly 0.0221mol KClO3. then you multiply the number of moles by the molar ratio of KClO3 to Oxygen to find the number of moles of oxygen produced. 0.0221 mol KClO3 x molar ratio (3O2/2KClO3) (notice KCLO3 in numerator and denominator so it cancels out leaving you with the moles of oxygen when you multiply the two quantities, so you get 0.0221 x(3/2) = 0.0332 mol of oxygen. 0.0332 mol x (32g O2/1mol) = 1.1g O2 you would follow a similar process for the other steps ensuring that you convert milligrams to grams before you do any calculations.
  • Photon336
note this reaction is a decomposition going from A-->B+C. Also note that they told you this reaction has gone to completion, so you don't have to find a limiting reagent. if you did however, you would find which compound is limiting FIRST and then calculate the number of moles/grams of products produced by using the limiting reagent.

Looking for something else?

Not the answer you are looking for? Search for more explanations.