anonymous
  • anonymous
Solve the system of equations. 2x-3y+z=-1 3x+2y+2z=-1 x-y-3z=-4
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
this stuff is a real pain let the machine do it
anonymous
  • anonymous
you know how?
anonymous
  • anonymous
Not a clue

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
Which machine?
anonymous
  • anonymous
http://www.wolframalpha.com/input/?i=+2x-3y%2Bz%3D-1%2C+3x%2B2y%2B2z%3D-1%2C+x-y-3z%3D-4
anonymous
  • anonymous
Thank you!
anonymous
  • anonymous
the machine you are typing on
anonymous
  • anonymous
yw
anonymous
  • anonymous
I have another question
anonymous
  • anonymous
The graph of which quadratic equation has a vertex of (-2,1). Y=(x+1)^2-2 Y=(x-1)^2-2 Y=(x+2)^2+1 Y=(x-2)^2+1
SolomonZelman
  • SolomonZelman
need it by hand (for question 1), then I would suggest matrix. it is already in order for a matrix.
anonymous
  • anonymous
I got the answer to the first question. And I don't know matrix
SolomonZelman
  • SolomonZelman
oh.
SolomonZelman
  • SolomonZelman
`y=(x-h)²+k` has a vertex (h,k)
SolomonZelman
  • SolomonZelman
now, where would this (h,k) be (-2,1) ? In which of the options?
anonymous
  • anonymous
Y=(x-1)^2+1
SolomonZelman
  • SolomonZelman
y=(x-h)²+k you need vertex (-2,1) and in that form the vertex is (h,k) so h=-2, k=1 y=(x- (-2) )² + (1) y= ? (you tell me....)
anonymous
  • anonymous
Um I'm not really sure
misty1212
  • misty1212
HI!!
SolomonZelman
  • SolomonZelman
Hello :)
misty1212
  • misty1212
where did your \(-1\) come from? \[y=(x-\color{blue}h)^2+\color{red}k\] put \[\color{blue}h=\color{blue}{-2}\] and \[\color{red}k=\color{red}1\]
anonymous
  • anonymous
My bad I meant to put 2 not 1
misty1212
  • misty1212
final answer?
anonymous
  • anonymous
That's what I'm trying to figure out and I can't seem to get it
misty1212
  • misty1212
it is a straight forward substitution plug in the numbers as above that is all
anonymous
  • anonymous
So y=(X-2)^2+1?
misty1212
  • misty1212
no dear, the minus sign comes with the number
anonymous
  • anonymous
So y=(x+2)^2+1?
misty1212
  • misty1212
\[y=(x-(-2))^2+1\] but of course you don't want to write \(-(-2)\)
misty1212
  • misty1212
yeah that one has vertex \((-2,1)\)
anonymous
  • anonymous
Thank you! I actually understand it now!
misty1212
  • misty1212
\[\color\magenta\heartsuit\]

Looking for something else?

Not the answer you are looking for? Search for more explanations.