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anonymous

  • one year ago

Solve the system of equations. 2x-3y+z=-1 3x+2y+2z=-1 x-y-3z=-4

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  1. anonymous
    • one year ago
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    this stuff is a real pain let the machine do it

  2. anonymous
    • one year ago
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    you know how?

  3. anonymous
    • one year ago
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    Not a clue

  4. anonymous
    • one year ago
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    Which machine?

  5. anonymous
    • one year ago
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    http://www.wolframalpha.com/input/?i=+2x-3y%2Bz%3D-1%2C+3x%2B2y%2B2z%3D-1%2C+x-y-3z%3D-4

  6. anonymous
    • one year ago
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    Thank you!

  7. anonymous
    • one year ago
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    the machine you are typing on

  8. anonymous
    • one year ago
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    yw

  9. anonymous
    • one year ago
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    I have another question

  10. anonymous
    • one year ago
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    The graph of which quadratic equation has a vertex of (-2,1). Y=(x+1)^2-2 Y=(x-1)^2-2 Y=(x+2)^2+1 Y=(x-2)^2+1

  11. SolomonZelman
    • one year ago
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    need it by hand (for question 1), then I would suggest matrix. it is already in order for a matrix.

  12. anonymous
    • one year ago
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    I got the answer to the first question. And I don't know matrix

  13. SolomonZelman
    • one year ago
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    oh.

  14. SolomonZelman
    • one year ago
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    `y=(x-h)²+k` has a vertex (h,k)

  15. SolomonZelman
    • one year ago
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    now, where would this (h,k) be (-2,1) ? In which of the options?

  16. anonymous
    • one year ago
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    Y=(x-1)^2+1

  17. SolomonZelman
    • one year ago
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    y=(x-h)²+k you need vertex (-2,1) and in that form the vertex is (h,k) so h=-2, k=1 y=(x- (-2) )² + (1) y= ? (you tell me....)

  18. anonymous
    • one year ago
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    Um I'm not really sure

  19. misty1212
    • one year ago
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    HI!!

  20. SolomonZelman
    • one year ago
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    Hello :)

  21. misty1212
    • one year ago
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    where did your \(-1\) come from? \[y=(x-\color{blue}h)^2+\color{red}k\] put \[\color{blue}h=\color{blue}{-2}\] and \[\color{red}k=\color{red}1\]

  22. anonymous
    • one year ago
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    My bad I meant to put 2 not 1

  23. misty1212
    • one year ago
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    final answer?

  24. anonymous
    • one year ago
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    That's what I'm trying to figure out and I can't seem to get it

  25. misty1212
    • one year ago
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    it is a straight forward substitution plug in the numbers as above that is all

  26. anonymous
    • one year ago
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    So y=(X-2)^2+1?

  27. misty1212
    • one year ago
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    no dear, the minus sign comes with the number

  28. anonymous
    • one year ago
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    So y=(x+2)^2+1?

  29. misty1212
    • one year ago
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    \[y=(x-(-2))^2+1\] but of course you don't want to write \(-(-2)\)

  30. misty1212
    • one year ago
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    yeah that one has vertex \((-2,1)\)

  31. anonymous
    • one year ago
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    Thank you! I actually understand it now!

  32. misty1212
    • one year ago
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    \[\color\magenta\heartsuit\]

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