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anonymous
 one year ago
I need some help on this question, I have been stuck on it for a while.
An expression is shown below:
f(x) = 16x2 + 22x + 3
Part A: What are the xintercepts of the graph of the f(x)? Show your work.
Part B: Is the vertex of the graph of f(x) going to be a maximum or minimum? What are the coordinates of the vertex? Justify your answers and show your work.
Part C: What are the steps you would use to graph f(x)? Justify that you can use the answers obtained in Part A and Part B to draw the graph
anonymous
 one year ago
I need some help on this question, I have been stuck on it for a while. An expression is shown below: f(x) = 16x2 + 22x + 3 Part A: What are the xintercepts of the graph of the f(x)? Show your work. Part B: Is the vertex of the graph of f(x) going to be a maximum or minimum? What are the coordinates of the vertex? Justify your answers and show your work. Part C: What are the steps you would use to graph f(x)? Justify that you can use the answers obtained in Part A and Part B to draw the graph

This Question is Closed

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2hmm... I can only do a. b and c  I forgot anyway to obtain the xintercepts set your y to 0 f(x) = y 0=16x^2+2x+3

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay I think if I can get A I might be able to get the rest. Oh okay thanks.

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1the vertex is going to absolute maximum if parabola opens down, and absolute minimum of parabola opens up. (to know opens up/down look at the coefficient of x²)

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1if coefficient of x² is negative it opens down, if positive then up.

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1you can graph it by hand (part C), using the obvious yintercept, the xintercept from part A, and perhaps you might want some more points for accuracy.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh wow thank you that helped a lot!
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