mckenzieandjesus
  • mckenzieandjesus
please help
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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mckenzieandjesus
  • mckenzieandjesus
@jim_thompson5910
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anonymous
  • anonymous
Help with what though?
mckenzieandjesus
  • mckenzieandjesus
jim_thompson5910 is helping me through message but he needed to see these images

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mckenzieandjesus
  • mckenzieandjesus
I need help with this though Find the area of the triangle. 24 square units 11 square units 12 square units 5.5 square units
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anonymous
  • anonymous
Area of a triangle is \[\large A=\frac{1}{2}\times height \times base\] The base is going to be the distance between the two bottom points. The height will be the distance between the middle of the base and the top point.
mckenzieandjesus
  • mckenzieandjesus
so the base would be 6?
anonymous
  • anonymous
Correct.
mckenzieandjesus
  • mckenzieandjesus
and 5 for height?
mckenzieandjesus
  • mckenzieandjesus
so 15?
anonymous
  • anonymous
Close, it would be 4
mckenzieandjesus
  • mckenzieandjesus
oops okay thanku!
anonymous
  • anonymous
\[\huge \color{aqua}N\color{fuchsia}o \space \color{lime}P \color{orange}r \color{blue}o \color{maroon}b \color{red}l \color{olive}e \color{purple}m \ddot\smile \]
mckenzieandjesus
  • mckenzieandjesus
this is for the 4 circles image A point in the figure is selected at random. Find the probability that the point will be in the part that is NOT shaded.
mckenzieandjesus
  • mckenzieandjesus
@LegendarySadist
anonymous
  • anonymous
Do they give you any units, or no?
mckenzieandjesus
  • mckenzieandjesus
@jim_thompson5910
mckenzieandjesus
  • mckenzieandjesus
no
anonymous
  • anonymous
Well as we can see, the lengths of 2 diameters is the same as the length as one side of the square. If we say that the length of the side of the square is 4, then that means that the diameter of a circle is 1/4th that, or 1. Can you figure out the areas from that?
mckenzieandjesus
  • mckenzieandjesus
Im confused with this one too, i keep getting an answer thats not on my multiple choice Find the area of the kite. 190.44 m2 126.96 m2 253.92 m2 380.88 m2
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jim_thompson5910
  • jim_thompson5910
multiply the diagonals, then divide by 2
jim_thompson5910
  • jim_thompson5910
the diagonal lengths are given in pieces, so you'll have to add them up first
mckenzieandjesus
  • mckenzieandjesus
so theres 4 sides to a square 4+4+4+4= 16 and 16/ 1/4= 64 did i do it right?
mckenzieandjesus
  • mckenzieandjesus
@jim_thompson5910 all 4 of them?
jim_thompson5910
  • jim_thompson5910
the longer diagonal is 6.9+13.8 = 20.7
jim_thompson5910
  • jim_thompson5910
do the same for the other diagonal multiply the diagonals, then divide by 2
mckenzieandjesus
  • mckenzieandjesus
so 6.9+13.8= 20.7 9.2+9.2= 18 2/5
mckenzieandjesus
  • mckenzieandjesus
my calc isnt letting me put in 2/5 after 18
mckenzieandjesus
  • mckenzieandjesus
ok its 380.88/2 = 190 11/25
mckenzieandjesus
  • mckenzieandjesus
so 190.44 m2 ?
mckenzieandjesus
  • mckenzieandjesus
@LegendarySadist so theres 4 sides to a square 4+4+4+4= 16 and 16/ 1/4= 64 did i do it right?
anonymous
  • anonymous
Area of a square is \[\large A=side^{2}\] and area of a circle is \[\large A=\pi r^{2}\]
mckenzieandjesus
  • mckenzieandjesus
so \[4^{2} + 4^{2} + 4^{2} + 4^{2} = 64 ?\]
anonymous
  • anonymous
Where are the 4 squares that you're adding together? What? It's JUST \(4^{2}\)
anonymous
  • anonymous
\[\large 4^{2}=16\] Boom, now we have the area of the square.
mckenzieandjesus
  • mckenzieandjesus
\[4^{2}= 16\]
mckenzieandjesus
  • mckenzieandjesus
oops
mckenzieandjesus
  • mckenzieandjesus
\[16\div \frac{ 1 }{ 4 } = 64\]
anonymous
  • anonymous
Now we find the area of the circle and multiply it by 4. Area of a circle is \(A=\pi r^{2}\) so if we want that times 4 it would look like \[\large A=4\pi r^{2}\] and HOW ARE YOU GETTING 64????
mckenzieandjesus
  • mckenzieandjesus
u said the diameter of a circle is 1/4th that? above^
mckenzieandjesus
  • mckenzieandjesus
sorry got confused.. what do i put for r?
mckenzieandjesus
  • mckenzieandjesus
so 4*3.14*5^2 = 314 could i do that or?
anonymous
  • anonymous
So the diamater of two circles is the side length. So \[\large 2d=side\] Since the radius is half of the diamater, it would be \[\large 4r=side\] The side is 4, as we know, so it would be \[\large 4r=4\] which makes \[\large r=1\]
mckenzieandjesus
  • mckenzieandjesus
so 4*3.14*1^2 = 12 14/25
anonymous
  • anonymous
Yeah. Now to find the area of the unshaded region, just do \[\large Area~of~square~~-~~Area~of~circles~=~Area~of~unshaded~region\]
mckenzieandjesus
  • mckenzieandjesus
so 16-12 14/25= 86/25
mckenzieandjesus
  • mckenzieandjesus
so 25%? or?
anonymous
  • anonymous
To find the chance of getting the unshaded region, so \[\large \frac{Area~of~Unshaded~region}{Area~of~square}\]
mckenzieandjesus
  • mckenzieandjesus
\[\frac{ 86 }{ 25 } \div 16 = \frac{ 43 }{ 200 }\]
mckenzieandjesus
  • mckenzieandjesus
thats not on my answers though..
anonymous
  • anonymous
In percentage form, it's 21.5% tho
mckenzieandjesus
  • mckenzieandjesus
yeah in decimal form its 0.215 so i guess i got confused
mckenzieandjesus
  • mckenzieandjesus
should of converted the decimal to percentage oops
mckenzieandjesus
  • mckenzieandjesus
thank you!
anonymous
  • anonymous
\[\huge \color{aqua}N\color{fuchsia}o \space \color{lime}P \color{orange}r \color{blue}o \color{maroon}b \color{red}l \color{olive}e \color{purple}m \ddot\smile \]

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