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anonymous

  • one year ago

An archer releases an arrow from a shoulder height of 1.39 m. When the arrow hits the target 18 m away, it hits point A. When the target is removed, the arrow lands 45 m away. Find the maximum height of the arrow along its parabolic path.

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  1. anonymous
    • one year ago
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    @dan815

  2. anonymous
    • one year ago
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    @Luigi0210

  3. anonymous
    • one year ago
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    Help meh coconut guy

  4. anonymous
    • one year ago
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    :c

  5. anonymous
    • one year ago
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    so far i drew the graph

  6. anonymous
    • one year ago
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    idk how to get the maximum height

  7. CoconutJJ
    • one year ago
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    ermm... is the arrow released parallel to the ground

  8. anonymous
    • one year ago
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    no its released from 1.39

  9. anonymous
    • one year ago
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    and its a parabola so it won't be parallel to the ground

  10. anonymous
    • one year ago
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    its curvy like a parabola ._.

  11. anonymous
    • one year ago
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    ITS A PARABOLA

  12. CoconutJJ
    • one year ago
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    You can have a parabola with an initial angle too though!

  13. anonymous
    • one year ago
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    ._.

  14. anonymous
    • one year ago
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    |dw:1435308134687:dw|

  15. CoconutJJ
    • one year ago
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    According to your graph the max height would be 1.39m, however the question seems to easy

  16. anonymous
    • one year ago
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    :O i just want to know how to find the maximum

  17. CoconutJJ
    • one year ago
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    Hmm let f(x) = ax^2+bc+c f(0) = 1.39 f(18) = (Height of point A) 16cm? f(45) = 0

  18. CoconutJJ
    • one year ago
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    bx*

  19. anonymous
    • one year ago
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    :O

  20. CoconutJJ
    • one year ago
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    c = y intercept c = initial height c= 1.39. You see where I'm going?

  21. anonymous
    • one year ago
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    ya

  22. CoconutJJ
    • one year ago
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    no.. solve the system of equations. plug in f(0), f(18) and f(45)

  23. anonymous
    • one year ago
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    ok wait

  24. CoconutJJ
    • one year ago
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    since we already know c... which is 1.39

  25. anonymous
    • one year ago
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    nope I'm really lost

  26. CoconutJJ
    • one year ago
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    a(0)^2+b(0)+1.39=0 a(18)^2+b(18)+1.39=height of arrow a(45)^2+b(45)+1.39=0

  27. anonymous
    • one year ago
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    hmmm

  28. CoconutJJ
    • one year ago
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    I suppose the arrow's height should be 0.16m from the ground...

  29. CoconutJJ
    • one year ago
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    no wait...

  30. anonymous
    • one year ago
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    1.71 is wat im getting

  31. anonymous
    • one year ago
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    ??

  32. CoconutJJ
    • one year ago
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    I found this yahoo answers just now about the exact question. They use a similar approach. However I'm confused on how you would find the height of the arrow, the diagram only gives the height of the sections https://answers.yahoo.com/question/index?qid=20121015160405AAfjtCu

  33. anonymous
    • one year ago
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    :/ confusing

  34. CoconutJJ
    • one year ago
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    ^ I'm not quite sure what the height of point A is... Most likely 0.16m from the ground since it lies 4 section above the bottom of the target

  35. MrNood
    • one year ago
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    I am almost certain that the question does not give enough information to solve this as it stands. You NEED to know the height of point A from the GROUND and that is not given I guess we also have to assume that they mean "if the target was NOT present the arrow would land at 45m" ot htat eh second shot without the target is EXACTLY the aame trajectory. |dw:1435311494413:dw|

  36. MrNood
    • one year ago
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    |dw:1435311610682:dw|

  37. phi
    • one year ago
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    See http://openstudy.com/study#/updates/52741308e4b09c259a0f64a7

  38. MrNood
    • one year ago
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    OK - THAT answer above has got more information - and gives the value for the height of A as required. it IS solvable once you have that information @Icedragon - was the height of the target given on YOUR drawing?

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