anonymous
  • anonymous
An archer releases an arrow from a shoulder height of 1.39 m. When the arrow hits the target 18 m away, it hits point A. When the target is removed, the arrow lands 45 m away. Find the maximum height of the arrow along its parabolic path.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
http://assets.openstudy.com/updates/attachments/507e201be4b0919a3cf31396-ducky_fresh-1350443065381-target.png
anonymous
  • anonymous
@dan815
anonymous
  • anonymous
@Luigi0210

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More answers

anonymous
  • anonymous
Help meh coconut guy
anonymous
  • anonymous
:c
anonymous
  • anonymous
so far i drew the graph
anonymous
  • anonymous
idk how to get the maximum height
CoconutJJ
  • CoconutJJ
ermm... is the arrow released parallel to the ground
anonymous
  • anonymous
no its released from 1.39
anonymous
  • anonymous
and its a parabola so it won't be parallel to the ground
anonymous
  • anonymous
its curvy like a parabola ._.
anonymous
  • anonymous
ITS A PARABOLA
CoconutJJ
  • CoconutJJ
You can have a parabola with an initial angle too though!
anonymous
  • anonymous
._.
anonymous
  • anonymous
|dw:1435308134687:dw|
CoconutJJ
  • CoconutJJ
According to your graph the max height would be 1.39m, however the question seems to easy
anonymous
  • anonymous
:O i just want to know how to find the maximum
CoconutJJ
  • CoconutJJ
Hmm let f(x) = ax^2+bc+c f(0) = 1.39 f(18) = (Height of point A) 16cm? f(45) = 0
CoconutJJ
  • CoconutJJ
bx*
anonymous
  • anonymous
:O
CoconutJJ
  • CoconutJJ
c = y intercept c = initial height c= 1.39. You see where I'm going?
anonymous
  • anonymous
ya
CoconutJJ
  • CoconutJJ
no.. solve the system of equations. plug in f(0), f(18) and f(45)
anonymous
  • anonymous
ok wait
CoconutJJ
  • CoconutJJ
since we already know c... which is 1.39
anonymous
  • anonymous
nope I'm really lost
CoconutJJ
  • CoconutJJ
a(0)^2+b(0)+1.39=0 a(18)^2+b(18)+1.39=height of arrow a(45)^2+b(45)+1.39=0
anonymous
  • anonymous
hmmm
CoconutJJ
  • CoconutJJ
I suppose the arrow's height should be 0.16m from the ground...
CoconutJJ
  • CoconutJJ
no wait...
anonymous
  • anonymous
1.71 is wat im getting
anonymous
  • anonymous
??
CoconutJJ
  • CoconutJJ
I found this yahoo answers just now about the exact question. They use a similar approach. However I'm confused on how you would find the height of the arrow, the diagram only gives the height of the sections https://answers.yahoo.com/question/index?qid=20121015160405AAfjtCu
anonymous
  • anonymous
:/ confusing
CoconutJJ
  • CoconutJJ
^ I'm not quite sure what the height of point A is... Most likely 0.16m from the ground since it lies 4 section above the bottom of the target
MrNood
  • MrNood
I am almost certain that the question does not give enough information to solve this as it stands. You NEED to know the height of point A from the GROUND and that is not given I guess we also have to assume that they mean "if the target was NOT present the arrow would land at 45m" ot htat eh second shot without the target is EXACTLY the aame trajectory. |dw:1435311494413:dw|
MrNood
  • MrNood
|dw:1435311610682:dw|
MrNood
  • MrNood
OK - THAT answer above has got more information - and gives the value for the height of A as required. it IS solvable once you have that information @Icedragon - was the height of the target given on YOUR drawing?

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