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vera_ewing

  • one year ago

3 of 15 Which of the following statements is true regarding the dissolution of a salt in a solvent? A. An equilibrium constant can be described that is the product of the concentrations of the ions to the power of their coefficient. B. The reaction does not have an equilibrium constant since all dissolution reactions are nonreversible. C. Precipitates are included in the equilibrium constant. D. The number of each ion does not affect the equilibrium constant.

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  1. vera_ewing
    • one year ago
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    @sweetburger

  2. anonymous
    • one year ago
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    it's b

  3. sweetburger
    • one year ago
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    It is not b.

  4. anonymous
    • one year ago
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    oops

  5. sweetburger
    • one year ago
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    All dissociation reactions will have Equilibrium constants in the form of Ksp values.

  6. sweetburger
    • one year ago
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    Besides that I believe the correct answer would be A. As B,C, and D are all incorrect. And A does make sense mathematically.

  7. vera_ewing
    • one year ago
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    Thank you. This one?

  8. sweetburger
    • one year ago
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    Products over reactants and H2O is a liquid so it drops out

  9. sweetburger
    • one year ago
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    Hmm these answers seem off.

  10. sweetburger
    • one year ago
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    I'm almost completely sure it should be [H3O+][CH3COO-]/[CH3COOH]

  11. sweetburger
    • one year ago
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    Oh its C. I completely missed it XD.

  12. anonymous
    • one year ago
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    I think the answer is B, because the Kc expression must apply for aqueous substances only and H2O is liquid. Solids and liquids should be out.

  13. vera_ewing
    • one year ago
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    Thank you it was C. ________equilibrium is a type of ________equilibrium which occurs when a reaction is ________. A. Dynamic; chemical; irreversible B. Dynamic; chemical; reversible C. Chemical; dynamic; irreversible D. Chemical; dynamic; reversible

  14. anonymous
    • one year ago
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    I mean C.

  15. sweetburger
    • one year ago
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    It cannot be A or C. A dynamic equilibrium will always be reversible.

  16. rvc
    • one year ago
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    B

  17. sweetburger
    • one year ago
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    Im almost sure it should be D. As a chemical equilibrium would fall under the classification of a dynamic equilibirum.

  18. rvc
    • one year ago
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    lol D

  19. rvc
    • one year ago
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    sorry im multitasking

  20. vera_ewing
    • one year ago
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    Yep, thanks it was D. This one?

  21. rvc
    • one year ago
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    C?

  22. sweetburger
    • one year ago
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    C looks good.

  23. vera_ewing
    • one year ago
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    Which of the following choices is not a potential application of the solubility product constant? A. Determine reactant concentrations that will allow a precipitate to form. B. Determine ion concentrations that will prevent a precipitate from forming. C. Determine ion concentrations that will allow a precipitate to form. D. Use Ksp to find solubility.

  24. sweetburger
    • one year ago
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    Well you can use Ksp to find solubility so it cant be D.

  25. sweetburger
    • one year ago
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    I'm actually not to sure on this one. I'm trying to think through it, but not much is coming up.

  26. sweetburger
    • one year ago
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    Actually it cannot be C either as you can determine how much of a ion will cause a precipitate to form.

  27. vera_ewing
    • one year ago
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    So it's either A or B?

  28. sweetburger
    • one year ago
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    Ya, I think so.

  29. vera_ewing
    • one year ago
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    Which one is the most logical answer?

  30. sweetburger
    • one year ago
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    I'm leaning towards A after thinking through it, but I'm still not completely sure with this question.

  31. vera_ewing
    • one year ago
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    It was A! :)

  32. sweetburger
    • one year ago
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    Haha, nice. :)

  33. vera_ewing
    • one year ago
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    This one?

  34. sweetburger
    • one year ago
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    I think this is just a Ksp problem in disguise, but Im not completely sure. So im going to say that 1.5x10^-8=[x][x] and then take the square root of both sides and get that x=.000122. That is equivalent to saying that [Pb2+]=1.22x10^-4.

  35. vera_ewing
    • one year ago
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    Thank you! The solubility of a substance is the _____ amount of the substance that can dissolve to form a _____ in a given amount of a particular solvent at a specified temperature. A. minimum; solution B. minimum; precipitate C. maximum; precipitate D. maximum; stable solution

  36. sweetburger
    • one year ago
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    maximum amount to form a stable solution

  37. vera_ewing
    • one year ago
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    thanks. how about this one?

  38. sweetburger
    • one year ago
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    No matter how insoluble we say a substance is something will always dissolve this even holds true for nonpolar substances being dissolved in polar substances and vice-versa. In this case the determined value of Ksp is so extremely small that we qualify it as insoluble.

  39. sweetburger
    • one year ago
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    So C.

  40. vera_ewing
    • one year ago
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    What is the solubility product constant (Ksp)? A. The equilibrium constant for the formation of any ionic compound B. The equilibrium constant for the formation of a nearly insoluble ionic compound C. The equilibrium constant for the dissolution of any ionic compound D. The equilibrium constant for the dissolution of a nearly insoluble ionic compound

  41. sweetburger
    • one year ago
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    C.

  42. vera_ewing
    • one year ago
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    It was D.

  43. vera_ewing
    • one year ago
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  44. vera_ewing
    • one year ago
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    @sweetburger How about this one?

  45. sweetburger
    • one year ago
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    B. As CaCO4 Ksp is 2.4x10^-5 and PbSO4 Ksp is 1.7x10^-8 adn CaCO4 has the larger Ksp value meaning it will be more soluble.

  46. vera_ewing
    • one year ago
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    Thank you.

  47. vera_ewing
    • one year ago
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    Not so sure about this one. A or B maybe?

  48. sweetburger
    • one year ago
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    Yes, I believe it would be. Think about it like this the Keq value is Products/Reactants if there are more reactants than prodcuts and I am just using arbitrary number here you will see that 1/100 = .01 which is a much smaller value then for example 100/1= 100 if there were more products than reactants . So when there are far more reactants at equilbirum the Keq value will be far less than 1. So B should be the correct answer. As for this example the Keq values is 1x10^-3 which is far smaller than 1.

  49. vera_ewing
    • one year ago
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    So A or B?

  50. sweetburger
    • one year ago
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    Im pretty sure B.

  51. vera_ewing
    • one year ago
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    What does a dissolved salt look like? A. The salt crystals are surrounded by water molecules. B. The salt crystals separate into salt molecules in the water. C. The ions in the salt are surrounded by water molecules. D. The salt separates into ions that settle to the bottom.

  52. sweetburger
    • one year ago
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    This should be C. as the positive ions will be surrounded by polar negative Oxygens from H2O molecules and the negative ions will be surrounded by polar positive Hydrogens from the H2O molecules.

  53. vera_ewing
    • one year ago
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    Question 15 of 15 What is solubility a measure of? A. The energy needed for the solute to dissolve B. The amount of solute that will dissolve C. The type of solute that will dissolve D. The rate at which the solute will dissolve

  54. vera_ewing
    • one year ago
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    @rvc @Hoslos ???

  55. anonymous
    • one year ago
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    D.

  56. rvc
    • one year ago
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    D

  57. vera_ewing
    • one year ago
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    Ah it was B. Thanks though.

  58. sweetburger
    • one year ago
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    Yea Ksp has nothing to do with Kinetics

  59. vera_ewing
    • one year ago
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    Thank you all so much for your help! I'm very thankful that you all helped me today! :) @Hoslos :) @rvc :) @sweetburger :)

  60. sweetburger
    • one year ago
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    Np :) @vera_ewing sorry I wasnt here for the last question :/

  61. vera_ewing
    • one year ago
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    No worries :)

  62. rvc
    • one year ago
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    All the best @Hoslos @sweetburger thanks 4 helping me to help her

  63. sweetburger
    • one year ago
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    :)

  64. anonymous
    • one year ago
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    I am glad. It was a good team discussion here though.

  65. sweetburger
    • one year ago
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    Agreed @Hoslos . Well done to everybody :).

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