The top of a ladder is 10 meters from the ground when the ladder leans against the wall at an angle of 35.5° with respect to the ground. If the ladder is moved by x meters toward the wall, it makes an angle of 54.5° with the ground, and its top is 14 meters above the ground. What is x rounded to the nearest meter? A) 7 meters B) 4 meters C) 3 meters D) 1 meters

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The top of a ladder is 10 meters from the ground when the ladder leans against the wall at an angle of 35.5° with respect to the ground. If the ladder is moved by x meters toward the wall, it makes an angle of 54.5° with the ground, and its top is 14 meters above the ground. What is x rounded to the nearest meter? A) 7 meters B) 4 meters C) 3 meters D) 1 meters

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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is this your pic? |dw:1435328917468:dw|
There is no picture with it, so I couldn't tell you.

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oh gee. i didnt scroll down there is a photo
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Well, if you're allowed to use a calculator with tan on it then it's pretty simple.
ok. so that's just a mirror image of the one I drew. and the 4 makes the problem a little easier. 1. You need to find the length of the part labeled T using a tan ratio. tan 35.5° = 10/T 2. find the length of the part labeled P using a tan ratio tan 54.5 = 14/P 3. subtract x = T - P|dw:1435329223674:dw|
Express tan(35.5) as 10/(the big cathetus). Express tan(54.5) as 14/(the small cathethus) Use your calculator to computer tan(35.5) and tan(54.5) and then equate above. Therefore, (the big cathetus) = 10/tan(35.5) (the small cathethus) = 14/tan(54.5) You calculate these and then x=(the big cathetus) - (the small cathethus)
Okay, okay.
Makes sense so far.
I think the answer is B, but I am probably wrong.
that's right

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