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anonymous

  • one year ago

The top of a ladder is 10 meters from the ground when the ladder leans against the wall at an angle of 35.5° with respect to the ground. If the ladder is moved by x meters toward the wall, it makes an angle of 54.5° with the ground, and its top is 14 meters above the ground. What is x rounded to the nearest meter? A) 7 meters B) 4 meters C) 3 meters D) 1 meters

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  1. anonymous
    • one year ago
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    @AngusV

  2. anonymous
    • one year ago
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    is this your pic? |dw:1435328917468:dw|

  3. anonymous
    • one year ago
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    There is no picture with it, so I couldn't tell you.

  4. anonymous
    • one year ago
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    oh gee. i didnt scroll down there is a photo

  5. anonymous
    • one year ago
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  6. anonymous
    • one year ago
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    @AngusV

  7. anonymous
    • one year ago
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    Well, if you're allowed to use a calculator with tan on it then it's pretty simple.

  8. anonymous
    • one year ago
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    ok. so that's just a mirror image of the one I drew. and the 4 makes the problem a little easier. 1. You need to find the length of the part labeled T using a tan ratio. tan 35.5° = 10/T 2. find the length of the part labeled P using a tan ratio tan 54.5 = 14/P 3. subtract x = T - P|dw:1435329223674:dw|

  9. anonymous
    • one year ago
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    Express tan(35.5) as 10/(the big cathetus). Express tan(54.5) as 14/(the small cathethus) Use your calculator to computer tan(35.5) and tan(54.5) and then equate above. Therefore, (the big cathetus) = 10/tan(35.5) (the small cathethus) = 14/tan(54.5) You calculate these and then x=(the big cathetus) - (the small cathethus)

  10. anonymous
    • one year ago
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    Okay, okay.

  11. anonymous
    • one year ago
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    Makes sense so far.

  12. anonymous
    • one year ago
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    I think the answer is B, but I am probably wrong.

  13. anonymous
    • one year ago
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    that's right

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