anonymous
  • anonymous
On Line DE D = (-3,-3) and E (2,4). Find point F on line DE so that DF and EF form a 1:3 ratio.
Mathematics
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anonymous
  • anonymous
On Line DE D = (-3,-3) and E (2,4). Find point F on line DE so that DF and EF form a 1:3 ratio.
Mathematics
chestercat
  • chestercat
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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anonymous
  • anonymous
Hello?
anonymous
  • anonymous
anonymous
  • anonymous
1:3 ratio means there are 4 segments on the line (1 + 3 = 4). Start by finding the "length" of each segment in x an y. \[x_{length}=\frac{ |x _2-x_1| }{ 4 }\] \[y_{length}=\frac{ |y _2-y_1| }{ 4 }\]

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anonymous
  • anonymous
xlength 5/4 and ylength= 7/5
anonymous
  • anonymous
7/4 for y.
anonymous
  • anonymous
soorry i meant 7/4
anonymous
  • anonymous
and then since you want a 1:3 ratio, add those to point D one time to get F.|dw:1435330209613:dw|
anonymous
  • anonymous
-7/4, 1?
anonymous
  • anonymous
-7/4 is right for x. I got -5/4 for y
anonymous
  • anonymous
-3+7 = 4 , 4/4 = 1?
anonymous
  • anonymous
need common denominator |dw:1435331274155:dw|

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