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Saylilbaby
 one year ago
help i will also give a medal...
Saylilbaby
 one year ago
help i will also give a medal...

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0CONFUSING LOOKING LOL

rvc
 one year ago
Best ResponseYou've already chosen the best response.0@VincentLyon.Fr @freckles

Australopithecus
 one year ago
Best ResponseYou've already chosen the best response.0This is actually really easy Note that you can factor some polynomials. What you have to do is simply look at the y intercepts in the graph. given an example the following graph: dw:1435336071585:dw NOTE this graph has the point in it (1, 6)

Australopithecus
 one year ago
Best ResponseYou've already chosen the best response.0Note point notation (x,y) 1. List out the yintercepts. In this example we have yintercepts: (1,0), (0,0), and (2,0) 2. Look at this like a factoring problem which is essentially setting up a polynomial so all its yintercepts are evident. We can deduce that the polynomial has the form based on its yintercept (x+1)(x2)x note this agrees with our graph! when, x = 1 ((1)+1)(x2)x = 0(x2)x = 0 when, x = 0 (0)(x+1)(x2) = 0 when, x = 2 ((2)2)(x+1)x = 0(x+1)x = 0 3. Lastly we need to check to see if the point present in the graph is present in the function we just created to model the graph. THe point given is (1, 6) plug x = 1 into our function (x+1)(x2)x (1+1)(12)*1 = 2*1*1 = 2 Notice that what we get is not correct!! Our function doesnt seem to be modeling our graph correctly! DOn't worry this can be fixed easily by using coefficients! What coefficient multiplied by 2 will give 6? the answer is 3 so just multiply 3 by our function 3(x+1)(x2)x now when x = 1 3(2) = 6 we have modeled the graph

Australopithecus
 one year ago
Best ResponseYou've already chosen the best response.0Let me know if you follow, I dont think I could explain it any clearer
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