Anyone please help me Expanding each integer in the expression 21 × 12, the result is [(2 × 101) + (1 × 100)] × [(1 × 101) + (2 × 100)]. Replace the 10s with x’s and then multiply this expression using FOIL. Compare it with the normal integer multiplication method used above: How are they similar? Show your work.

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Anyone please help me Expanding each integer in the expression 21 × 12, the result is [(2 × 101) + (1 × 100)] × [(1 × 101) + (2 × 100)]. Replace the 10s with x’s and then multiply this expression using FOIL. Compare it with the normal integer multiplication method used above: How are they similar? Show your work.

Mathematics
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Can you help me, I just need some basic knowledge of this
ganeshie8

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okay so uhh, they say replace the 10s with xs
is there some typo in the question or something
because that is definately not the result of 21*12
ok thank and how is the normal integer multipication method similar to FOIL
No i dont think there is a typo
okay well you see you can do foil stuff with integer multiplication
for example 21* 12 = (20+1) * (10 +2 )
wow ok tht helps
so if you break that up further you get this
(20+1) * (10 +2 ) = 20*(10+2) + 1*(10+2) = 20*10 + 20*2 + 1*10 + 1*2 =200 +40 + 10 + 2 = 252
Foil is a formula that is like a shortcut to this expansion
nvm, i dont wanna overload you with this stuff, its pointless
it's just expanding brackets thats all you need to know
no i think i get the basics of this now at least
Thank you!!
I was totally confused at first
okay then great :)

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