HELP PRECALC GIVING MEDALS AND BECOMING A FAN 1.)Find an explicit rule for the nth term of the sequence. -4, -8, -16, -32 an = -4 • 2^(n - 1) an = 2 • -4^(n + 1) an = 2 • -4^n an = -4 • 2^n 2.) Find an explicit rule for the nth term of a geometric sequence where the second and fifth terms are -12 and 768, respectively. an = 3 • (-4)^(n + 1) an = 3 • 4^(n - 1) an = 3 • (-4)^(n - 1) an = 3 • 4^n

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HELP PRECALC GIVING MEDALS AND BECOMING A FAN 1.)Find an explicit rule for the nth term of the sequence. -4, -8, -16, -32 an = -4 • 2^(n - 1) an = 2 • -4^(n + 1) an = 2 • -4^n an = -4 • 2^n 2.) Find an explicit rule for the nth term of a geometric sequence where the second and fifth terms are -12 and 768, respectively. an = 3 • (-4)^(n + 1) an = 3 • 4^(n - 1) an = 3 • (-4)^(n - 1) an = 3 • 4^n

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HI!!
you can always check which ones work, but each term in negative, so the number out fron must be negative
For Question one this is answer: an = -4 • 2n - 1

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if \(n=1\) you should get \(-4\) and i think only \[-4\times 2^{n-1}\] works
@misty1212 so is an = -4 • 2^(n - 1) correct?
yes
thank you both @misty1212 for the second question I know it isn't an = 3 • 4^(n - 1) but i hv no idea what it is
you are supposed to get something that looks like \[a_n=a_0\times r^{n-1}\]
\[a_2=-12\\ a_5=768\]
is it A? @misty1212
divide and get \[\frac{a_5}{a_2}=\frac{768}{-12}=-64\]
idk i can't eyeball it, we have to do it
that means \[r^3=-64\] so \[r=-4\]
then go with C since it is the one that looks like \[a_0r^{n-1}\] in this case \(r=-4\) and \(a_0=3\) since \[3\times (-4)^{2-1}=3\times -4=-12\]
thanks @misty1212

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