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anonymous
 one year ago
HELP PRECALC GIVING MEDALS AND BECOMING A FAN
1.)Find an explicit rule for the nth term of the sequence.
4, 8, 16, 32
an = 4 2^(n  1)
an = 2 4^(n + 1)
an = 2 4^n
an = 4 2^n
2.) Find an explicit rule for the nth term of a geometric sequence where the second and fifth terms are 12 and 768, respectively.
an = 3 (4)^(n + 1)
an = 3 4^(n  1)
an = 3 (4)^(n  1)
an = 3 4^n
anonymous
 one year ago
HELP PRECALC GIVING MEDALS AND BECOMING A FAN 1.)Find an explicit rule for the nth term of the sequence. 4, 8, 16, 32 an = 4 2^(n  1) an = 2 4^(n + 1) an = 2 4^n an = 4 2^n 2.) Find an explicit rule for the nth term of a geometric sequence where the second and fifth terms are 12 and 768, respectively. an = 3 (4)^(n + 1) an = 3 4^(n  1) an = 3 (4)^(n  1) an = 3 4^n

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misty1212
 one year ago
Best ResponseYou've already chosen the best response.1you can always check which ones work, but each term in negative, so the number out fron must be negative

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0For Question one this is answer: an = 4 • 2n  1

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1if \(n=1\) you should get \(4\) and i think only \[4\times 2^{n1}\] works

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@misty1212 so is an = 4 • 2^(n  1) correct?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0thank you both @misty1212 for the second question I know it isn't an = 3 4^(n  1) but i hv no idea what it is

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1you are supposed to get something that looks like \[a_n=a_0\times r^{n1}\]

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1\[a_2=12\\ a_5=768\]

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1divide and get \[\frac{a_5}{a_2}=\frac{768}{12}=64\]

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1idk i can't eyeball it, we have to do it

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1that means \[r^3=64\] so \[r=4\]

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1then go with C since it is the one that looks like \[a_0r^{n1}\] in this case \(r=4\) and \(a_0=3\) since \[3\times (4)^{21}=3\times 4=12\]
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