anonymous
  • anonymous
HELP PRECALC GIVING MEDALS AND BECOMING A FAN 1.)Find an explicit rule for the nth term of the sequence. -4, -8, -16, -32 an = -4 • 2^(n - 1) an = 2 • -4^(n + 1) an = 2 • -4^n an = -4 • 2^n 2.) Find an explicit rule for the nth term of a geometric sequence where the second and fifth terms are -12 and 768, respectively. an = 3 • (-4)^(n + 1) an = 3 • 4^(n - 1) an = 3 • (-4)^(n - 1) an = 3 • 4^n
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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misty1212
  • misty1212
HI!!
misty1212
  • misty1212
you can always check which ones work, but each term in negative, so the number out fron must be negative
anonymous
  • anonymous
For Question one this is answer: an = -4 • 2n - 1

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misty1212
  • misty1212
if \(n=1\) you should get \(-4\) and i think only \[-4\times 2^{n-1}\] works
anonymous
  • anonymous
@misty1212 so is an = -4 • 2^(n - 1) correct?
misty1212
  • misty1212
yes
anonymous
  • anonymous
thank you both @misty1212 for the second question I know it isn't an = 3 • 4^(n - 1) but i hv no idea what it is
anonymous
  • anonymous
@freckles
misty1212
  • misty1212
you are supposed to get something that looks like \[a_n=a_0\times r^{n-1}\]
misty1212
  • misty1212
\[a_2=-12\\ a_5=768\]
anonymous
  • anonymous
is it A? @misty1212
misty1212
  • misty1212
divide and get \[\frac{a_5}{a_2}=\frac{768}{-12}=-64\]
misty1212
  • misty1212
idk i can't eyeball it, we have to do it
misty1212
  • misty1212
that means \[r^3=-64\] so \[r=-4\]
misty1212
  • misty1212
then go with C since it is the one that looks like \[a_0r^{n-1}\] in this case \(r=-4\) and \(a_0=3\) since \[3\times (-4)^{2-1}=3\times -4=-12\]
anonymous
  • anonymous
thanks @misty1212

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