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anonymous
 one year ago
1. x – 3 > –9
2. –2x + 1 ≤ –11
3. 10 < –3x + 1
4. 2(x + 5) > 8x – 8
5. –2(x – 3) ≥ 5 – (x + 3)
Solve each and graph for each
anonymous
 one year ago
1. x – 3 > –9 2. –2x + 1 ≤ –11 3. 10 < –3x + 1 4. 2(x + 5) > 8x – 8 5. –2(x – 3) ≥ 5 – (x + 3) Solve each and graph for each

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0how would i graph this

AbdullahM
 one year ago
Best ResponseYou've already chosen the best response.1dw:1435336629065:dw

AbdullahM
 one year ago
Best ResponseYou've already chosen the best response.1You could use: https://www.desmos.com/calculator

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i mean on a number line sorry

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0it would be an open circle?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Do you have a website for the number line?

AbdullahM
 one year ago
Best ResponseYou've already chosen the best response.1essentially, you can use the website and only look at the xaxis

AbdullahM
 one year ago
Best ResponseYou've already chosen the best response.1and since you see the graph has a dashed line, that means an open circle. When the line on the graph is solid, then that means a closed circle.

AbdullahM
 one year ago
Best ResponseYou've already chosen the best response.1dw:1435336897914:dw this has a dashed line so it means open circle

AbdullahM
 one year ago
Best ResponseYou've already chosen the best response.1I drew an orange box around the dashed line.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0alright i can graph the rest i just need help solving the rest

anonymous
 one year ago
Best ResponseYou've already chosen the best response.02x +1 < 11 \[2x +1 \le 11\]

AbdullahM
 one year ago
Best ResponseYou've already chosen the best response.1for graphing it on a number line: dw:1435337002162:dw

AbdullahM
 one year ago
Best ResponseYou've already chosen the best response.1For #2, we would first take the +1 to the other side. So we have to subtract that on both sides.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.02x less than or equal to 12

AbdullahM
 one year ago
Best ResponseYou've already chosen the best response.1now we have \(\sf 2x\le 12\)

AbdullahM
 one year ago
Best ResponseYou've already chosen the best response.1Do you know that when you divide by a negative number on both sides that the sign flips

AbdullahM
 one year ago
Best ResponseYou've already chosen the best response.1For example: \(\sf\Large x \le 5\) then \(\sf\Large x \ge 5\) another example: \(\sf\Large 2y > 6\) then \(\sf\Large y<3\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0does it ever switch from \[\le \to \]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0without the line under it

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0but this answer is x=6

AbdullahM
 one year ago
Best ResponseYou've already chosen the best response.1\(\color{blue}{\text{Originally Posted by}}\) @AbdullahM now we have \(\sf 2x\le 12\) \(\color{blue}{\text{End of Quote}}\) if we divide 2, and also we have to change the sign, what do we get?

AbdullahM
 one year ago
Best ResponseYou've already chosen the best response.1no, it would be \(\sf\Large x\ge6\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yeah thats i meant my b

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0could i also say greater than or equal to?

AbdullahM
 one year ago
Best ResponseYou've already chosen the best response.1remember these are the opposites: \(\sf \le\) and \(\sf \ge\) are opposites < and > are opposites

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0and this circle would be open?

AbdullahM
 one year ago
Best ResponseYou've already chosen the best response.1http://prntscr.com/7ln08a from: http://www.studyzone.org/mtestprep/math8/a/graphing_inequalities7l.cfm

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1435337698545:dw

AbdullahM
 one year ago
Best ResponseYou've already chosen the best response.110 < –3x + 1 lets make our life easier and not have to do the switching signs. So lets take 3x to the other side by addition

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0+3x both sides 3x + 10 < 1 3x < 9 x< 3

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1435338193021:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i might have made a mistake

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Should i have flipped the sign?

AbdullahM
 one year ago
Best ResponseYou've already chosen the best response.1splendid work, you made no mistakes :)

AbdullahM
 one year ago
Best ResponseYou've already chosen the best response.1we only flip the sign when we divide by a negative number

AbdullahM
 one year ago
Best ResponseYou've already chosen the best response.1First we have to take care of 2(x+5) distribute the 2 inside

anonymous
 one year ago
Best ResponseYou've already chosen the best response.08x both sides 6x + 10 > 8 10 both sides 6x> 18 divide 6 both sides x < 3

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1435338649893:dw

AbdullahM
 one year ago
Best ResponseYou've already chosen the best response.1wow, amazing work once again! :D

anonymous
 one year ago
Best ResponseYou've already chosen the best response.02(x  3) > 5  (x +3)

AbdullahM
 one year ago
Best ResponseYou've already chosen the best response.1–2(x – 3) ≥ 5 – (x + 3) this time we have both sides where we have to dsitribute. Be careful, they have a negative number outside that needs to be distributed

anonymous
 one year ago
Best ResponseYou've already chosen the best response.02x + 6 > 5 x  3 @AbdullahM ?

AbdullahM
 one year ago
Best ResponseYou've already chosen the best response.1no we can add the 2x to both sides and work from there :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0+x both sides x + 6 > 53 6 both sides x > 4 divide by 1 x < 4

AbdullahM
 one year ago
Best ResponseYou've already chosen the best response.1so we don't have to divide by a negative number on both sides, but it seems like you have mastered that trick anyways :D

AbdullahM
 one year ago
Best ResponseYou've already chosen the best response.1not really a rtick, more like a rule xD

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yeah :p i thought it' be easier

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1435339061662:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Explain, in complete sentences, when you would use an open circle or a closed circle, and when you would shade to the right or left, to graph an inequality on the number line. (3 points) 7. Describe a real life scenario where inequalities are used and state the inequality. (2 points)

AbdullahM
 one year ago
Best ResponseYou've already chosen the best response.1\(\color{blue}{\text{Originally Posted by}}\) @AbdullahM http://prntscr.com/7ln08a from: http://www.studyzone.org/mtestprep/math8/a/graphing_inequalities7l.cfm \(\color{blue}{\text{End of Quote}}\) use this for the first question

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0alright and i think i did my last graph wrong

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1435339286981:dw

AbdullahM
 one year ago
Best ResponseYou've already chosen the best response.1open circle, not closed. and everything else is correct

AbdullahM
 one year ago
Best ResponseYou've already chosen the best response.1for the second question, you can use: http://openstudy.com/study#/updates/4f188153e4b00328e4c52f91 http://openstudy.com/study#/updates/50fb45a6e4b010aceb32e484 http://openstudy.com/study#/updates/511e6d1fe4b06821731bf312 https://answers.yahoo.com/question/index?qid=20100719235617AABwik9

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@AbdullahM Thank you for the help! You are a great teacher :)

AbdullahM
 one year ago
Best ResponseYou've already chosen the best response.1anytime, that's why I'm on OpenStudy to help.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0That's all i need for today but i'll hit ya up if i need help another time, Have a good afternoon!
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