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anonymous

  • one year ago

When adding two numbers, such as 123 and 423, care is taken to first line them up and then add like digits. How does expanding this expression to [(1 × 102) + (2 × 101) + (3 × 100)] + [(4 × 102) + (2 × 101) + (3 × 100)] make the operation more like a polynomial addition problem?

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  1. anonymous
    • one year ago
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    @dan815

  2. anonymous
    • one year ago
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    How does it make it like a polynomial expression problem

  3. dan815
    • one year ago
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    oh now I see omg

  4. dan815
    • one year ago
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    thats why i was getting*confused! those are exponent ofcourse

  5. anonymous
    • one year ago
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    ohh maybe an example of a polynomial expression problem will help

  6. dan815
    • one year ago
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    |dw:1435337338251:dw|

  7. dan815
    • one year ago
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    if you change the 10 to Xs

  8. dan815
    • one year ago
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    |dw:1435337431925:dw|

  9. dan815
    • one year ago
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    so you see how with polynomial addition

  10. dan815
    • one year ago
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    we always add the like terms or the same degree terms we cannot add numbers infront of x^2 to x

  11. dan815
    • one year ago
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    so you see how addition is very similiar to the same thing we do with polynomial addition?

  12. anonymous
    • one year ago
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    yeah I see now

  13. dan815
    • one year ago
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    theyre trying to show you how adding like terms is very similiar to the normal addition which we do already without thinking about it

  14. anonymous
    • one year ago
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    ok i get it now i was just confused onhow polynomial addition works

  15. dan815
    • one year ago
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    k good

  16. dan815
    • one year ago
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    and in the future use latex or put ^ infront of exponents like 10^2 and 10^1

  17. anonymous
    • one year ago
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    oh ok will do :)

  18. dan815
    • one year ago
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    you should learn latex now, its good to start early

  19. dan815
    • one year ago
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    |dw:1435337874001:dw|

  20. dan815
    • one year ago
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    use those symbols

  21. dan815
    • one year ago
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    \[10^2\]

  22. dan815
    • one year ago
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    \[\int \frac{a}{b}dx e^x\]

  23. anonymous
    • one year ago
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    first time learning that ok

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