Fan & Medal a. Use transformations of a common graph to obtain the graph of f. b. Find the slope-intercept equation of the tangent line to the graph of f at the point whose x-coordinate is given. c. Use the y-intercept and the slope to graph the tangent line in the same rectangular coordinate system as the graph of f. f(x)=(x+2)^2; tangent line at -1

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Fan & Medal a. Use transformations of a common graph to obtain the graph of f. b. Find the slope-intercept equation of the tangent line to the graph of f at the point whose x-coordinate is given. c. Use the y-intercept and the slope to graph the tangent line in the same rectangular coordinate system as the graph of f. f(x)=(x+2)^2; tangent line at -1

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|dw:1435346200845:dw|
ok

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note the graph of f would be |dw:1435346832213:dw|
|dw:1435346954681:dw|
i cant see what that is in black
|dw:1435347043886:dw|
what u cant see?
in red whats circled you have something written in black its cut off
|dw:1435340167275:dw|
that part would be the gradient
oh ok
|dw:1435347461250:dw|
so far i understand
this parts now :c.Use the y-intercept and the slope to graph the tangent line in the same rectangular coordinate system as the graph of f.
y intercept=3 slope=2 so (2,3) is where the tangent will cut the graph
ok can you sketch the graph?
1 Attachment
of y=2x+3 i mean
1 Attachment
|dw:1435348760188:dw|
Thank You for all your help, you helped me alot though you might not think so.@LynFran
ur welcome

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