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anonymous

  • one year ago

Fan & Medal a. Use transformations of a common graph to obtain the graph of f. b. Find the slope-intercept equation of the tangent line to the graph of f at the point whose x-coordinate is given. c. Use the y-intercept and the slope to graph the tangent line in the same rectangular coordinate system as the graph of f. f(x)=(x+2)^2; tangent line at -1

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  1. anonymous
    • one year ago
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    @LynFran

  2. LynFran
    • one year ago
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    |dw:1435346200845:dw|

  3. anonymous
    • one year ago
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    ok

  4. LynFran
    • one year ago
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    note the graph of f would be |dw:1435346832213:dw|

  5. LynFran
    • one year ago
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    |dw:1435346954681:dw|

  6. anonymous
    • one year ago
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    i cant see what that is in black

  7. LynFran
    • one year ago
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    |dw:1435347043886:dw|

  8. LynFran
    • one year ago
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    what u cant see?

  9. anonymous
    • one year ago
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    in red whats circled you have something written in black its cut off

  10. anonymous
    • one year ago
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    |dw:1435340167275:dw|

  11. LynFran
    • one year ago
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    that part would be the gradient

  12. anonymous
    • one year ago
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    oh ok

  13. LynFran
    • one year ago
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    |dw:1435347461250:dw|

  14. anonymous
    • one year ago
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    so far i understand

  15. LynFran
    • one year ago
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    this parts now :c.Use the y-intercept and the slope to graph the tangent line in the same rectangular coordinate system as the graph of f.

  16. LynFran
    • one year ago
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    y intercept=3 slope=2 so (2,3) is where the tangent will cut the graph

  17. LynFran
    • one year ago
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    ok can you sketch the graph?

  18. anonymous
    • one year ago
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  19. LynFran
    • one year ago
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    of y=2x+3 i mean

  20. anonymous
    • one year ago
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  21. LynFran
    • one year ago
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    |dw:1435348760188:dw|

  22. anonymous
    • one year ago
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    Thank You for all your help, you helped me alot though you might not think so.@LynFran

  23. LynFran
    • one year ago
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    ur welcome

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