## anonymous one year ago Fan & Medal a. Use transformations of a common graph to obtain the graph of f. b. Find the slope-intercept equation of the tangent line to the graph of f at the point whose x-coordinate is given. c. Use the y-intercept and the slope to graph the tangent line in the same rectangular coordinate system as the graph of f. f(x)=(x+2)^2; tangent line at -1

1. anonymous

@LynFran

2. LynFran

|dw:1435346200845:dw|

3. anonymous

ok

4. LynFran

note the graph of f would be |dw:1435346832213:dw|

5. LynFran

|dw:1435346954681:dw|

6. anonymous

i cant see what that is in black

7. LynFran

|dw:1435347043886:dw|

8. LynFran

what u cant see?

9. anonymous

in red whats circled you have something written in black its cut off

10. anonymous

|dw:1435340167275:dw|

11. LynFran

that part would be the gradient

12. anonymous

oh ok

13. LynFran

|dw:1435347461250:dw|

14. anonymous

so far i understand

15. LynFran

this parts now :c.Use the y-intercept and the slope to graph the tangent line in the same rectangular coordinate system as the graph of f.

16. LynFran

y intercept=3 slope=2 so (2,3) is where the tangent will cut the graph

17. LynFran

ok can you sketch the graph?

18. anonymous

19. LynFran

of y=2x+3 i mean

20. anonymous

21. LynFran

|dw:1435348760188:dw|

22. anonymous

Thank You for all your help, you helped me alot though you might not think so.@LynFran

23. LynFran

ur welcome