anonymous
  • anonymous
I've been trying to figure this out for a long time. What is the answer? The sum of three consecutive integers is 267. What is the largest integer?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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welshfella
  • welshfella
if the 3 consecutive numbers are n , n+1 and n+2 then we have the equation n + n + 1 + n + 2 = 267 solve for n
welshfella
  • welshfella
the largest integer will be n + 2.
anonymous
  • anonymous
where are you getting n from?

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welshfella
  • welshfella
n is a symbol for the lowest of the 3 integers i could have used n , m x y or any letter
welshfella
  • welshfella
this is algebra
anonymous
  • anonymous
ok thank you
welshfella
  • welshfella
can you solve it or do you want me to show you how ?
anonymous
  • anonymous
is the final answer n+2 or is there more stuff to do?
welshfella
  • welshfella
no there is some more manipulation to do n at present is unknown and we need to find its value . n in words can be described as ' some integer' and we can describe the equation in words as 'there is an unknown integer which when added to the next consecutive integer and to the next integer after that gives a total of 267' the next 2 integers are of course n+1 and n + 2
welshfella
  • welshfella
when we add 3 n's we write it as 3n ( which is like 3 times n but the multiply is left out and 1 + 2 is of course 3 so the equation becomes 3n + 3 = 267
anonymous
  • anonymous
I think the final answer is 90. is that right?
welshfella
  • welshfella
yes n = 88 and 3 numbers are 88,89 and 90
anonymous
  • anonymous
ok thank you!
welshfella
  • welshfella
yw

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