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anonymous

  • one year ago

I've been trying to figure this out for a long time. What is the answer? The sum of three consecutive integers is 267. What is the largest integer?

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  1. welshfella
    • one year ago
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    if the 3 consecutive numbers are n , n+1 and n+2 then we have the equation n + n + 1 + n + 2 = 267 solve for n

  2. welshfella
    • one year ago
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    the largest integer will be n + 2.

  3. anonymous
    • one year ago
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    where are you getting n from?

  4. welshfella
    • one year ago
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    n is a symbol for the lowest of the 3 integers i could have used n , m x y or any letter

  5. welshfella
    • one year ago
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    this is algebra

  6. anonymous
    • one year ago
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    ok thank you

  7. welshfella
    • one year ago
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    can you solve it or do you want me to show you how ?

  8. anonymous
    • one year ago
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    is the final answer n+2 or is there more stuff to do?

  9. welshfella
    • one year ago
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    no there is some more manipulation to do n at present is unknown and we need to find its value . n in words can be described as ' some integer' and we can describe the equation in words as 'there is an unknown integer which when added to the next consecutive integer and to the next integer after that gives a total of 267' the next 2 integers are of course n+1 and n + 2

  10. welshfella
    • one year ago
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    when we add 3 n's we write it as 3n ( which is like 3 times n but the multiply is left out and 1 + 2 is of course 3 so the equation becomes 3n + 3 = 267

  11. anonymous
    • one year ago
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    I think the final answer is 90. is that right?

  12. welshfella
    • one year ago
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    yes n = 88 and 3 numbers are 88,89 and 90

  13. anonymous
    • one year ago
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    ok thank you!

  14. welshfella
    • one year ago
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    yw

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