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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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we have to compute the amount Q_1 of heat needed to melt that quantity of ice, and the amount Q_2 of heat needed to raise the temperature of the water from zero to 100 ┬░celsius degree, and the amount Q_3 of heat to transform all the water vapor in steam at 100 degrees. Now we have this: \[\Large \begin{gathered} {Q_1} = {\lambda _F}m = 79.7 \times 2 = ...kCal \hfill \\ \hfill \\ {Q_2} = {c_{{H_2}O}}m\Delta t = 1 \times 2 \times 100 = ...kCal \hfill \\ \hfill \\ {Q_3} = {\lambda _E}m = 539.2 \times 2 = ...kCal \hfill \\ \end{gathered} \] where: \[\Large {\lambda _F},\;{\lambda _E}\] are the latent heats of melting and vaporization of water respectively, and \[\Large {c_{{H_2}O}}\] is the specific heat of water Finally, the requested amount Q_Total of heat is given by the subsequent formula: \[\Large {Q_{Total}} = {Q_1} + {Q_2} + {Q_3} = ...\] Please complete my computation
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