anonymous
  • anonymous
? Consider the following equilibrium: 4KO2(s) + 2H2O(g) 4KOH(s) + 3O2(g) Which of the following is a correct equilibrium expression? Keq=[KOH]4[O2]3[KO2]4[H2O]2 Keq=[H2O]2[O2]3 Keq=[KO2]4[H2O]2[KOH]4[O2]3 Keq=[O2]3[H2O]2
Chemistry
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anonymous
  • anonymous
? Consider the following equilibrium: 4KO2(s) + 2H2O(g) 4KOH(s) + 3O2(g) Which of the following is a correct equilibrium expression? Keq=[KOH]4[O2]3[KO2]4[H2O]2 Keq=[H2O]2[O2]3 Keq=[KO2]4[H2O]2[KOH]4[O2]3 Keq=[O2]3[H2O]2
Chemistry
jamiebookeater
  • jamiebookeater
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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anonymous
  • anonymous
Photon336
  • Photon336
For the reaction 4KO2 (s) + 2H20(g) --- 4KOH (s) + 3O2(g) We never include the concentrations of pure solids or liquids or very dilute liquids, because for those substances the concentrations don't change much. Usually one includes the substances in the gaseous phase, so we can neglect the solids on the products and reactant sides. The equilibrium expression takes the concentration of the products raised to the power of their stoichiometric coefficient. So we have products/reactants So our equilibrium expression is the following: [O2]^3/[H2O]^2

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