anonymous
  • anonymous
Assuming equal concentrations and complete dissociation, rank these aqueous solutions by their freezing points. K2SO4 NH4I CoCl3
Chemistry
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
Photon336
  • Photon336
Assuming complete dissociation in aqueous solution Implies the following: 1) k2so4 (aq)--> 2K+ so4^-2 2) NH4I (aq)---> NH4+ I 3) CoCl3 (aq) ---> Co^+3 + 3Cl So now these are considered colligative properties meaning that it doesn't matter the identity of your molecule only how much stuff solute you dissolve into a solvent. If you dissolve something in a solvent in this case water, it lowers the freezing point. I guess one way to think about it is by figuring out how many mole of ions produced by each reaction Van hoff factor Reaction one we have 3 mole total Reaction two we have 1 mole I, 1 mole NH4 so 2 mole of ions Reaction 3 we have 4 mole total ions. The reaction that would lower the freezing point the most would produce the most ions. So reaction 3 would have the lowest freezing point followed by reaction 1 and then reaction 2.

Looking for something else?

Not the answer you are looking for? Search for more explanations.