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anonymous

  • one year ago

HELP PLEASE. Determine if the graph is symmetric about the x-axis, the y-axis, or the origin. r = -5 - 5 cos θ Origin only x-axis only y-axis only No symmetry

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  1. anonymous
    • one year ago
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    @dan815 @phi @Hero @Miss.SweetiePie

  2. anonymous
    • one year ago
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    @paki

  3. campbell_st
    • one year ago
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    have you graphed the curve..?

  4. anonymous
    • one year ago
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    yes @campbell_st

  5. campbell_st
    • one year ago
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    is it polar coordinates..?

  6. anonymous
    • one year ago
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    idk

  7. anonymous
    • one year ago
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    I got x-axis only

  8. campbell_st
    • one year ago
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    well can you post your graph...?

  9. anonymous
    • one year ago
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    after replacing θ with -θ ... r = -5 - 5 cos(-θ) which means that both are even function so that cos(-θ) = cos(θ) r = -5 - 5 cos θ

  10. anonymous
    • one year ago
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    @Miss.SweetiePie thank u so much!!!

  11. campbell_st
    • one year ago
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    lol...

  12. anonymous
    • one year ago
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    Your welcome @em2000 are you a fan yet?

  13. Michele_Laino
    • one year ago
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    we can rewrite thhat equation, using the cartesian coordinates, namely: \[\Large r = - 5 - 5\frac{x}{r}\] from which we get: \[\Large {x^2} + {y^2} + 5\sqrt {{x^2} + {y^2}} + 5x = 0\] Now it is easy to understand if there is a symmetry for that equation

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spraguer (Moderator)
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