anonymous
  • anonymous
Simplify- will medal and fan (−2⋅qp^3)^3 Select one: a. m^3⋅p^12⋅q^6 b. 27⋅q^3⋅p^9 c. 4⋅m^8⋅p^6⋅q^8 d. −8⋅q^3⋅p^9
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
campbell_st
  • campbell_st
the external power of 3 operates on each part inside the brackets \[(-2)^3 \times (p)^3 \times (q^3)^3\]
campbell_st
  • campbell_st
you should be able to simplify this
anonymous
  • anonymous
@AWillie98 do you sill need help?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
yes @Miss.SweetiePie
anonymous
  • anonymous
\[(-2)^{3}= -2 \times -2 \times -2 = -8\]
anonymous
  • anonymous
\[(p)^{3}=p ^{3}\]
anonymous
  • anonymous
\[(q ^{3})^{3}=q ^{9}\]
anonymous
  • anonymous
which gives you D
anonymous
  • anonymous
thank you @Miss.SweetiePie
anonymous
  • anonymous
any time
campbell_st
  • campbell_st
nice thing about this site, if you wait long enough someone always give the answer
anonymous
  • anonymous
@campbell_st who are you talking about????
campbell_st
  • campbell_st
the mantra of open study.... help improve understanding and don't give answers
campbell_st
  • campbell_st
@annas, perhaps the question was to difficult for open study
campbell_st
  • campbell_st
I choose to help for free... and many do... that way I can pick and choose... @annas

Looking for something else?

Not the answer you are looking for? Search for more explanations.