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anonymous

  • one year ago

If sin Θ = 1 over 4 and tan Θ > 0, what is the value of cos Θ?

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  1. anonymous
    • one year ago
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    negative square root of 15 square root of 15 square root of 15 over 4 negative square root of 15 over 4

  2. LynFran
    • one year ago
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    last option

  3. LynFran
    • one year ago
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    let me show u how ok

  4. anonymous
    • one year ago
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    ok

  5. Michele_Laino
    • one year ago
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    hint: |dw:1435348645865:dw|

  6. LynFran
    • one year ago
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    |dw:1435355888315:dw| the third option sorry

  7. Michele_Laino
    • one year ago
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    there are 2 angles which satisfy the condition: sin (x) = 1/4, nevertheless only one is the right one

  8. LynFran
    • one year ago
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    the third option is correct

  9. anonymous
    • one year ago
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    ohhhhh ok thank you both

  10. Michele_Laino
    • one year ago
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    :)

  11. anonymous
    • one year ago
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    1 more?

  12. Michele_Laino
    • one year ago
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    ok!

  13. anonymous
    • one year ago
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    Where are the asymptotes of f(x) = tan(2x − π) from x = pi over 2 to x = 3 pi over 2

  14. Michele_Laino
    • one year ago
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    we can write your function as below: \[\begin{gathered} \tan \left( {2x - \pi } \right) = \frac{{\tan \left( {2x} \right) - \tan \pi }}{{1 + \tan \left( {2x} \right)\tan \pi }} = \hfill \\ \hfill \\ = \tan \left( {2x} \right) = \frac{{\sin \left( {2x} \right)}}{{\cos \left( {2x} \right)}} \hfill \\ \end{gathered} \]

  15. anonymous
    • one year ago
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    O.O lemme get my calculator

  16. Michele_Laino
    • one year ago
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    now we have vertical asymptotes, at point x, such that: \[\cos \left( {2x} \right) = 0\]

  17. anonymous
    • one year ago
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    let me post my choices

  18. anonymous
    • one year ago
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    x = 3 pi over 4, x = 5 pi over 4 x = 0, x = π, x = 2π x = 0, x = pi over 4 x = pi over 2, x = 3 pi over 2

  19. Michele_Laino
    • one year ago
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    namely, when: \[2x = \frac{\pi }{2} + k\pi ,\quad k = 0, \pm 1, \pm 2,...\]

  20. anonymous
    • one year ago
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    D is wrong , right?

  21. Michele_Laino
    • one year ago
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    so dividing by 2, we get: \[x = \frac{\pi }{4} + k\frac{\pi }{2},\quad k = 0, \pm 1, \pm 2,...\]

  22. anonymous
    • one year ago
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    is it C

  23. Michele_Laino
    • one year ago
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    no, it is A

  24. anonymous
    • one year ago
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    but i thought you said one of them was 0

  25. anonymous
    • one year ago
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    oh i see

  26. Michele_Laino
    • one year ago
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    since, using my formula, we get: \[\frac{\pi }{4},\quad \frac{{3\pi }}{4},\quad \frac{{5\pi }}{4},\quad \frac{{7\pi }}{4},...\]

  27. anonymous
    • one year ago
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    yeah i just got that

  28. anonymous
    • one year ago
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    thank you if i could give another medal i would

  29. Michele_Laino
    • one year ago
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    ok! :)

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