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anonymous
 one year ago
MEDAL!!!!!!!!!
Functions f(x) and g(x) are shown below:
anonymous
 one year ago
MEDAL!!!!!!!!! Functions f(x) and g(x) are shown below:

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0f(x) = 3x2 + 12x + 16 g(x)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Using complete sentences, explain how to find the minimum value for each function and determine which function has the smallest minimum yvalue

welshfella
 one year ago
Best ResponseYou've already chosen the best response.2for f(x) value of x at minimum is b/2a ( that the a and b in the function ax^2 + bx + c) Then plug this into the formula for f(x) to get minimum value of f(x)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0g "(x) = 16sin(4x  π) > 0 for x = 5π/8, etc. So therefore, g(5π/8) = 2sin(π/4) + 4 = 4 + √2 > f(2) = 4

welshfella
 one year ago
Best ResponseYou've already chosen the best response.2For g(x) the minimum is at x = pi/2 so plug this into formula for g(x) to get the required minimum.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so f(x) isf '(x) = 6x + 12 =0 => x = 2

welshfella
 one year ago
Best ResponseYou've already chosen the best response.2oh ok  you are using calculus now plug 2 into f(x)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0is that the smallest y value

welshfella
 one year ago
Best ResponseYou've already chosen the best response.2yes g(x) is smallest minimum value

welshfella
 one year ago
Best ResponseYou've already chosen the best response.2i get minimum value of g(x) = 2

welshfella
 one year ago
Best ResponseYou've already chosen the best response.2g(x) = 2 sin (x  pi) g'(x) = 2 cos ( x  pi) = 0 at turning points

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0explain how to find the minimum value for each function

welshfella
 one year ago
Best ResponseYou've already chosen the best response.2using calculus you find the first derivative and equate it to zero and solve for x this will give you a critical point you can now test for maximum or minimum by taking the second derivative and finding its sign for the value of x you have found positive value is minimum and negative is a maximum.

welshfella
 one year ago
Best ResponseYou've already chosen the best response.2so for the first question f"(x) is 6 positive so thats a minimum

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0thanks for the help man
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