anonymous
  • anonymous
Which point could be removed in order to make the relation a function? {(–4, 3), (–5, 6), (1, 0), (–4, 5), (9, 5), (0, –7)}
Mathematics
jamiebookeater
  • jamiebookeater
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Australopithecus
  • Australopithecus
Every unput (x value) must have a unique output (y value) for a relation to be considered a function. The vertical line test can be used to determine if a relation is a function. If you can draw a vertical line that goes through a relation more than once it is a function This is a function by the vertical line test: |dw:1435352050788:dw| This is NOT a function by the vertical line test: |dw:1435352079662:dw| It fails the vertical line test, a line can pass through it more than once
Australopithecus
  • Australopithecus
Let me know if you follow
Australopithecus
  • Australopithecus
correction: If you can draw a vertical line that goes through a relation more than once it is NOT a function

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Australopithecus
  • Australopithecus
sorry about that
Australopithecus
  • Australopithecus
you could graph the points and do this test
Australopithecus
  • Australopithecus
graphing would be the safest bet, but you could also consider think about what I wrote: Every input (x value) must have a unique output (y value) for a relation to be considered a function. Ask yourself: -Are there two points with the same x coordinate with a different y coordinate in your relation. -Which point would cause the function to fail the vertical line test?
Australopithecus
  • Australopithecus
just to be clear: The graphs I did the vertical test on were as follows, the line I drew on top of them was the test itself: |dw:1435352616053:dw| |dw:1435352637672:dw|
anonymous
  • anonymous
(-4,3) and (-4,5) have the same x value
anonymous
  • anonymous
The pair that is messing up the vertical line is the answer?
omarbirjas
  • omarbirjas
Yes. You have to remove one of those.
omarbirjas
  • omarbirjas
Not that I know of.

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