## Keigh2015 one year ago If the area of a rectangle is 24a2b and the length is 8ab2, what would be the width of the rectangle, given that width is found by dividing area by length? Simplify the answer. the quantity of 3 times a all over b b over the quantity 3 times a 3 over the quantity a times b 3ab

1. Keigh2015

2. Falling_In_Katt

3a/b

3. anonymous

divide like the problem says $\frac{ 24a^2b }{ 8ab^2 }=\frac{ 24 }{ 8} \times \frac{ a^2 }{ a } \times \frac{ b }{ b^2 }$

4. Keigh2015