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Keigh2015
 one year ago
If the area of a rectangle is 24a2b and the length is 8ab2, what would be the width of the rectangle, given that width is found by dividing area by length? Simplify the answer.
the quantity of 3 times a all over b
b over the quantity 3 times a
3 over the quantity a times b
3ab
Keigh2015
 one year ago
If the area of a rectangle is 24a2b and the length is 8ab2, what would be the width of the rectangle, given that width is found by dividing area by length? Simplify the answer. the quantity of 3 times a all over b b over the quantity 3 times a 3 over the quantity a times b 3ab

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Keigh2015
 one year ago
Best ResponseYou've already chosen the best response.1@annas @Falling_In_Katt @uybuyvf @Poppies

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0divide like the problem says \[\frac{ 24a^2b }{ 8ab^2 }=\frac{ 24 }{ 8} \times \frac{ a^2 }{ a } \times \frac{ b }{ b^2 }\]

undeadknight26
 one year ago
Best ResponseYou've already chosen the best response.0Divide: 24(a^2)b / 8a(b^2) = 24/8 * a^2/a * b/b^2 = ? Taken from: http://openstudy.com/study#/updates/52a26555e4b0a13bbbe93f8d
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