Keigh2015
  • Keigh2015
If the area of a rectangle is 24a2b and the length is 8ab2, what would be the width of the rectangle, given that width is found by dividing area by length? Simplify the answer. the quantity of 3 times a all over b b over the quantity 3 times a 3 over the quantity a times b 3ab
Mathematics
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SOLVED
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jamiebookeater
  • jamiebookeater
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Keigh2015
  • Keigh2015
@annas @Falling_In_Katt @uybuyvf @Poppies
Falling_In_Katt
  • Falling_In_Katt
3a/b
anonymous
  • anonymous
divide like the problem says \[\frac{ 24a^2b }{ 8ab^2 }=\frac{ 24 }{ 8} \times \frac{ a^2 }{ a } \times \frac{ b }{ b^2 }\]

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Keigh2015
  • Keigh2015
@undeadknight26
undeadknight26
  • undeadknight26
Divide: 24(a^2)b / 8a(b^2) = 24/8 * a^2/a * b/b^2 = ? Taken from: http://openstudy.com/study#/updates/52a26555e4b0a13bbbe93f8d

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