anonymous
  • anonymous
How would I solve this problem? I'll post it in the comments.
Mathematics
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
mathmath333
  • mathmath333
have u heard about triplets
anonymous
  • anonymous
I'm not sure. I don't think so.

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mathmath333
  • mathmath333
if i was at ur place i would have checked with the options \(x^2+y^2=28\) which ever fits
mathmath333
  • mathmath333
it should be this \(\large \color{black}{\begin{align}&x^2+y^2=28^2\hspace{.33em}\\~\\ \end{align}}\)
mathmath333
  • mathmath333
this should be helpful \(\large \color{black}{\begin{align}&x^2-16^2=y^2-12^2\hspace{.33em}\\~\\ & x^2+y^2=28^2 \end{align}}\)
anonymous
  • anonymous
Wait, how did you get that?
mathmath333
  • mathmath333
|dw:1435359291063:dw|
mathmath333
  • mathmath333
\(\large \color{black}{\begin{align}&x^2=h^2+16^2\hspace{.33em}\\~\\ &y^2=h^2+12^2\hspace{.33em}\\~\\ \end{align}}\)

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