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  • briana.img
How do you write an equation for a hyperbola that involves foci?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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briana.img
  • briana.img
briana.img
  • briana.img
@jim_thompson5910 plz help you're the best
jim_thompson5910
  • jim_thompson5910
|dw:1435360080154:dw|

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More answers

jim_thompson5910
  • jim_thompson5910
Foci |dw:1435360096843:dw|
jim_thompson5910
  • jim_thompson5910
vertices |dw:1435360133480:dw|
jim_thompson5910
  • jim_thompson5910
what is the midpoint of the vertices? |dw:1435360163097:dw|
briana.img
  • briana.img
(4,0) ???
jim_thompson5910
  • jim_thompson5910
4 is correct 0 is not
briana.img
  • briana.img
(4,5)
jim_thompson5910
  • jim_thompson5910
good
jim_thompson5910
  • jim_thompson5910
|dw:1435360285728:dw|
jim_thompson5910
  • jim_thompson5910
The distance from the center to either vertex is what numeric value?
briana.img
  • briana.img
Ok I understand that the top half of the equation with be (x-4)^2 - (y-5)^2
jim_thompson5910
  • jim_thompson5910
correct
briana.img
  • briana.img
The distance from either vertex is two?
jim_thompson5910
  • jim_thompson5910
from center to vertex (pick one) is 2 units, yes
jim_thompson5910
  • jim_thompson5910
so a = 2 where \[\Large \frac{(x-h)^2}{a^2} - \frac{(y-k)^2}{b^2} = 1\]
jim_thompson5910
  • jim_thompson5910
'a' corresponds to the x portion because the hyperbola opens along the x axis direction (ie horizontally)
jim_thompson5910
  • jim_thompson5910
c = 3 because it is 3 units from the center to either focus use a^2 + b^2 = c^2 to find b
jim_thompson5910
  • jim_thompson5910
actually you don't need to solve for b you can stop at b^2 and that would be fine too
briana.img
  • briana.img
@jim_thompson5910 oh okay! i clearly understand now!! thank you :)
jim_thompson5910
  • jim_thompson5910
no problem

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