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anonymous
 one year ago
Solving Equations with multiplying and dividing.
1. y=32
2. 7r=56
3. t/3 =12
4. 4= s/14
5.b/47=2
P.S. "The / means its a fraction."
anonymous
 one year ago
Solving Equations with multiplying and dividing. 1. y=32 2. 7r=56 3. t/3 =12 4. 4= s/14 5.b/47=2 P.S. "The / means its a fraction."

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Keigh2015
 one year ago
Best ResponseYou've already chosen the best response.0I don't know this I am sorry. @alexistheking777 come take a look at this and @ianmack904 can you come look at this?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Its fine i been looking for help all day.

Keigh2015
 one year ago
Best ResponseYou've already chosen the best response.0I am sorry I couldn't be of anymore help

sammixboo
 one year ago
Best ResponseYou've already chosen the best response.2Let's do #5 ** We have \(\tt \color{red}{\dfrac{b}{47}= 2}\) To solve this you must: \(\tt \color{red}{Multiply~47~on~both~sides~of~the~equation.}\) So, now we have \(\tt \color{red}{\dfrac{b}{47}\times47= 2\times47}\) Do you know how to simplify this? Once you do, you will get your answer :)

sammixboo
 one year ago
Best ResponseYou've already chosen the best response.2And that's your answer for #5. Tell me what you got :)

sammixboo
 one year ago
Best ResponseYou've already chosen the best response.2Correcto ** Now let's do #4: \(\tt \color{red}{4= \dfrac{s}{14}}\) Do you have an idea on how to solve this?

sammixboo
 one year ago
Best ResponseYou've already chosen the best response.2Not quite, you would \(\tt \color{red}{multiply}\), since you are originally \(\tt \color{red}{dividing}\).

sammixboo
 one year ago
Best ResponseYou've already chosen the best response.2So, \(\tt \color{red}{14\times4}\)

sammixboo
 one year ago
Best ResponseYou've already chosen the best response.2Correct again ^^ #4 is 56. Let's do #3: \(\tt \color{red}{\dfrac{t}{3}=12}\) Do you know what to do on this one?

sammixboo
 one year ago
Best ResponseYou've already chosen the best response.2Right **, so #3 is 36 Now for #2, we do the opposite since we are originally multiplying. \(\tt \color{red}{7r=56}\) We have to \(\tt \color{red}{divide~7~on~both~sides}\). What do you think the answer is?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0UM...I GOT SUM REALLY LONG NUMBER

sammixboo
 one year ago
Best ResponseYou've already chosen the best response.2You shouldn't. Make sure you type 56/7 and not 7/56

sammixboo
 one year ago
Best ResponseYou've already chosen the best response.2Sure you typed everything correct?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yep stll got the long number

sammixboo
 one year ago
Best ResponseYou've already chosen the best response.2You typed 57/7, not 56/7

sammixboo
 one year ago
Best ResponseYou've already chosen the best response.2^^ It's ok. It happens a lot, and that is right, so #2 is 8

sammixboo
 one year ago
Best ResponseYou've already chosen the best response.2What do you think it is?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0cause u remeber the teachers saying if the letter by itself it counts as a 1 in front of it

sammixboo
 one year ago
Best ResponseYou've already chosen the best response.2Close, but not quite. Now for #1, we have \(\tt \color{red}{y = 32}\), since they are both negative, your answer should be positive

sammixboo
 one year ago
Best ResponseYou've already chosen the best response.2If y = 32, then we would have   32 = 32, which isn't right :P

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i think i can do the other 16 by myself

sammixboo
 one year ago
Best ResponseYou've already chosen the best response.2Okie dokie. Once you finish you can post it here and I can check it if you want.
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