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anonymous

  • one year ago

Solving Equations with multiplying and dividing. 1. -y=-32 2. 7r=-56 3. t/-3 =12 4. 4= s/-14 5.b/47=-2 P.S. "The / means its a fraction."

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  1. anonymous
    • one year ago
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    anyone can help me?

  2. Keigh2015
    • one year ago
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    I don't know this I am sorry. @alexistheking777 come take a look at this and @ianmack904 can you come look at this?

  3. anonymous
    • one year ago
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    Its fine i been looking for help all day.

  4. Keigh2015
    • one year ago
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    I am sorry I couldn't be of anymore help

  5. anonymous
    • one year ago
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    dont be srry, u ii

  6. sammixboo
    • one year ago
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    Let's do #5 *-* We have \(\tt \color{red}{\dfrac{b}{47}= -2}\) To solve this you must: \(\tt \color{red}{Multiply~47~on~both~sides~of~the~equation.}\) So, now we have \(\tt \color{red}{\dfrac{b}{47}\times47= -2\times47}\) Do you know how to simplify this? Once you do, you will get your answer :)

  7. anonymous
    • one year ago
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    so do -2x47?

  8. sammixboo
    • one year ago
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    Right

  9. sammixboo
    • one year ago
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    And that's your answer for #5. Tell me what you got :)

  10. anonymous
    • one year ago
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    b=(-94)

  11. sammixboo
    • one year ago
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    Correcto *-* Now let's do #4: \(\tt \color{red}{4= \dfrac{s}{-14}}\) Do you have an idea on how to solve this?

  12. anonymous
    • one year ago
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    i would do -14/4?

  13. sammixboo
    • one year ago
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    Not quite, you would \(\tt \color{red}{multiply}\), since you are originally \(\tt \color{red}{dividing}\).

  14. sammixboo
    • one year ago
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    So, \(\tt \color{red}{-14\times4}\)

  15. anonymous
    • one year ago
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    -56

  16. anonymous
    • one year ago
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    s=(-56)

  17. sammixboo
    • one year ago
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    Correct again ^-^ #4 is -56. Let's do #3: \(\tt \color{red}{\dfrac{t}{-3}=12}\) Do you know what to do on this one?

  18. anonymous
    • one year ago
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    12x-3?

  19. sammixboo
    • one year ago
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    Right, which is?

  20. anonymous
    • one year ago
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    t=-36

  21. sammixboo
    • one year ago
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    Right *-*, so #3 is -36 Now for #2, we do the opposite since we are originally multiplying. \(\tt \color{red}{7r=-56}\) We have to \(\tt \color{red}{divide~7~on~both~sides}\). What do you think the answer is?

  22. anonymous
    • one year ago
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    SO....-56/7

  23. sammixboo
    • one year ago
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    Yeppers :)

  24. anonymous
    • one year ago
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    UM...I GOT SUM REALLY LONG NUMBER

  25. sammixboo
    • one year ago
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    You shouldn't. Make sure you type -56/7 and not 7/-56

  26. anonymous
    • one year ago
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    i got -8.142857143

  27. sammixboo
    • one year ago
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    Sure you typed everything correct?

  28. anonymous
    • one year ago
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    yep stll got the long number

  29. sammixboo
    • one year ago
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    You typed -57/7, not -56/7

  30. anonymous
    • one year ago
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    X___x

  31. anonymous
    • one year ago
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    I GOT -8

  32. sammixboo
    • one year ago
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    ^-^ It's ok. It happens a lot, and that is right, so #2 is -8

  33. anonymous
    • one year ago
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    r=-8

  34. anonymous
    • one year ago
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    i think ik #1

  35. sammixboo
    • one year ago
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    What do you think it is?

  36. anonymous
    • one year ago
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    y=-32

  37. anonymous
    • one year ago
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    cause u remeber the teachers saying if the letter by itself it counts as a 1 in front of it

  38. sammixboo
    • one year ago
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    Close, but not quite. Now for #1, we have \(\tt \color{red}{-y = -32}\), since they are both negative, your answer should be positive

  39. anonymous
    • one year ago
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    OH OK

  40. anonymous
    • one year ago
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    y=32

  41. sammixboo
    • one year ago
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    If y = -32, then we would have - - 32 = -32, which isn't right :P

  42. sammixboo
    • one year ago
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    Right *-*

  43. sammixboo
    • one year ago
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    Good job :)

  44. anonymous
    • one year ago
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    YAY...i feel smart

  45. anonymous
    • one year ago
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    i think i can do the other 16 by myself

  46. sammixboo
    • one year ago
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    Okie dokie. Once you finish you can post it here and I can check it if you want.

  47. anonymous
    • one year ago
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    ok

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