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anonymous
 one year ago
A certain isotope decays so that the amount A remaining after t years is given by:
A = A0 • e ^(0.03t)
where A0 is the original amount of the isotope. To the nearest year, the halflife of the isotope (the amount of time it takes to decay to half the original amount) is ____ years.
anonymous
 one year ago
A certain isotope decays so that the amount A remaining after t years is given by: A = A0 • e ^(0.03t) where A0 is the original amount of the isotope. To the nearest year, the halflife of the isotope (the amount of time it takes to decay to half the original amount) is ____ years.

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0the entire thing! I dont even know how to start @Loser66

Loser66
 one year ago
Best ResponseYou've already chosen the best response.0A = 1/2 A0, solve for t. Dat sit

Loser66
 one year ago
Best ResponseYou've already chosen the best response.0\(A_0\) is the original amount of the isotope, right?

Loser66
 one year ago
Best ResponseYou've already chosen the best response.0\( A \) is the new amount of the original one, and it is = a half of original one. That means \(A=\dfrac{1}{2}A_0\)

Loser66
 one year ago
Best ResponseYou've already chosen the best response.0Now, put them in, you have \(\dfrac{1}{2}A_0=A_0e^{0.03t}\) simplify \(A_0\) and solve for t. I let you finish the stuff.
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