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anonymous

  • one year ago

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  1. Loser66
    • one year ago
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    |dw:1435366072497:dw|

  2. Loser66
    • one year ago
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    |dw:1435366106917:dw|

  3. Loser66
    • one year ago
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    Now, if it move - 210 degree, that is it move clockwise 210 degree, right? |dw:1435366249866:dw|

  4. Loser66
    • one year ago
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    on the other hand, if it moves counterclockwise 150 degree, where is the point it will stop?? |dw:1435366414951:dw|

  5. Loser66
    • one year ago
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    That means, go clockwise 210 and go counterclockwise 150 will end at the same point.

  6. Loser66
    • one year ago
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    @jim_thompson5910 Please, rescue me. I don't know how to ..... explain him

  7. Loser66
    • one year ago
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    Does it matter?? to me, no difference.

  8. jim_thompson5910
    • one year ago
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    |dw:1435367101428:dw|

  9. jim_thompson5910
    • one year ago
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    |dw:1435367124452:dw| whatever the point is, it will be in Q3

  10. jim_thompson5910
    • one year ago
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    oh wait

  11. jim_thompson5910
    • one year ago
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    it's -210

  12. jim_thompson5910
    • one year ago
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    |dw:1435367178589:dw|

  13. jim_thompson5910
    • one year ago
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    so it's some point in Q2

  14. jim_thompson5910
    • one year ago
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    np

  15. xapproachesinfinity
    • one year ago
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    the question said choose so you basically think of any point that can be on second quadrant but is the terminal of a vector that you draw from -210

  16. xapproachesinfinity
    • one year ago
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    well given you don't have those choices! according to this what do yo think is the answer

  17. xapproachesinfinity
    • one year ago
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    think of Quadrant II

  18. triciaal
    • one year ago
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    |dw:1435451078544:dw|

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spraguer (Moderator)
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is replying to Can someone tell me what button the professor is hitting...

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