## anonymous one year ago I am trying to solve the equation (5x-4)(4x+8)=0 using factoring. I keep getting stuck on this problem. Could someone please answer and explain how you got your answer? Thanks you! :)

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1. jim_thompson5910

If A*B = 0, then either A = 0 or B = 0

2. jim_thompson5910

So using that idea, we can go from (5x-4)(4x+8)=0 to 5x-4 = 0 or 4x+8 = 0

3. jim_thompson5910

Do you see how to finish up?

4. anonymous

Yes, thank you

5. jim_thompson5910

no problem

6. DecentNabeel

$\mathrm{Using\:the\:Zero\:Factor\:Principle:}$ $\mathrm{Solve\:}\:5x-4=0:\quad x=\frac{4}{5}$ $\mathrm{Solve\:}\:4x+8=0:\quad x=-2$ $\mathrm{The\:final\:solutions\:\to\:the\:quadratic\:equation\:are:}$ $x=\frac{4}{5},\:x=-2$ the answer is .. $\left(5x-4\right)\left(4x+8\right)=0\quad :\quad x=\frac{4}{5},\:x=-2$