anonymous
  • anonymous
1. The perimeter of a rectangle is 78 cm. The length is 3 greater than twice its width. Find the dimensions. Divide by 2 to get 39 then since a number is 3 times greater than a different number doubled do 3*2=6 so its six times greater
Mathematics
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anonymous
  • anonymous
1. The perimeter of a rectangle is 78 cm. The length is 3 greater than twice its width. Find the dimensions. Divide by 2 to get 39 then since a number is 3 times greater than a different number doubled do 3*2=6 so its six times greater
Mathematics
chestercat
  • chestercat
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anonymous
  • anonymous
draw the rectangle and write an equation. Let w = width. 3 greater than twice width is saying the length is 3 + 2w |dw:1435372479239:dw| All the sides add up to the perimeter, which is 78 so this is the equation \[2w + 2(3+2w)=78\]
anonymous
  • anonymous
do you know how to solve that for w?
anonymous
  • anonymous
I think i do let me try

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anonymous
  • anonymous
w=12 ?
anonymous
  • anonymous
yep. Now all that's left is to find the length. L = 3 + 2w
anonymous
  • anonymous
do i have to slove for w ?
anonymous
  • anonymous
so what can i write down as my answer ?
anonymous
  • anonymous
no you already have w = 12. so just plug in 12 for w to get L
anonymous
  • anonymous
so it would be 60 ?
anonymous
  • anonymous
just list the dimensions. width = 12 cm, length = 27 cm
anonymous
  • anonymous
L = 3 + 2w = 3 + 2(12) = 27
anonymous
  • anonymous
Thank you for your help !

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