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anonymous
 one year ago
1. The perimeter of a rectangle is 78 cm. The length is 3 greater than twice its width. Find the dimensions.
Divide by 2 to get 39 then since a number is 3 times greater than a different number doubled do 3*2=6 so its six times greater
anonymous
 one year ago
1. The perimeter of a rectangle is 78 cm. The length is 3 greater than twice its width. Find the dimensions. Divide by 2 to get 39 then since a number is 3 times greater than a different number doubled do 3*2=6 so its six times greater

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0draw the rectangle and write an equation. Let w = width. 3 greater than twice width is saying the length is 3 + 2w dw:1435372479239:dw All the sides add up to the perimeter, which is 78 so this is the equation \[2w + 2(3+2w)=78\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0do you know how to solve that for w?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I think i do let me try

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yep. Now all that's left is to find the length. L = 3 + 2w

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0do i have to slove for w ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so what can i write down as my answer ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0no you already have w = 12. so just plug in 12 for w to get L

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0just list the dimensions. width = 12 cm, length = 27 cm

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0L = 3 + 2w = 3 + 2(12) = 27

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Thank you for your help !
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