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anonymous
 one year ago
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The average cricket jumps vertically with an inital upward speed of 10 ft/s. What is the hang time of such a jump, ignoring air resistance? Use the formula h=16t^2+10t, where h is the height of the cricket in feet and t is the time in seconds after the jump. Round your answer to the nearest tenth.
A.
0.4 seconds
B.
0.6 seconds
C.
0.8 seconds
D.
1.0 second
anonymous
 one year ago
Need help The average cricket jumps vertically with an inital upward speed of 10 ft/s. What is the hang time of such a jump, ignoring air resistance? Use the formula h=16t^2+10t, where h is the height of the cricket in feet and t is the time in seconds after the jump. Round your answer to the nearest tenth. A. 0.4 seconds B. 0.6 seconds C. 0.8 seconds D. 1.0 second

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0am saying A but not sure or B

Compassionate
 one year ago
Best ResponseYou've already chosen the best response.0Hi, What would you define as, "Hang time."

Compassionate
 one year ago
Best ResponseYou've already chosen the best response.0So you know it travels at 10 ft/s You're given the formula h=16t^2+10t What do you think you should do? HINT: The Quadratic Formula

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0we calculate the time when h=0 i.e.,initially position and again when it comes on the ground. \[16 t^2+10t=0,2t \left( 8t5 \right)=0\] either 2t=0 \[\implies t=0\] it gives initial time. or 8 t5=0 \[t=\frac{ 5 }{ 8 }=0.625\] it gives final time. so it is in air ?
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