anonymous one year ago Need help The average cricket jumps vertically with an inital upward speed of 10 ft/s. What is the hang time of such a jump, ignoring air resistance? Use the formula h=-16t^2+10t, where h is the height of the cricket in feet and t is the time in seconds after the jump. Round your answer to the nearest tenth. A. 0.4 seconds B. 0.6 seconds C. 0.8 seconds D. 1.0 second

1. anonymous

am saying A but not sure or B

2. Compassionate

Hi, What would you define as, "Hang time."

3. anonymous

time in the air

4. Compassionate

So you know it travels at 10 ft/s You're given the formula h=-16t^2+10t What do you think you should do? HINT: The Quadratic Formula

5. anonymous

IT has to be A

6. anonymous

we calculate the time when h=0 i.e.,initially position and again when it comes on the ground. $-16 t^2+10t=0,-2t \left( 8t-5 \right)=0$ either -2t=0 $\implies t=0$ it gives initial time. or 8 t-5=0 $t=\frac{ 5 }{ 8 }=0.625$ it gives final time. so it is in air ?