anonymous
  • anonymous
Need help The average cricket jumps vertically with an inital upward speed of 10 ft/s. What is the hang time of such a jump, ignoring air resistance? Use the formula h=-16t^2+10t, where h is the height of the cricket in feet and t is the time in seconds after the jump. Round your answer to the nearest tenth. A. 0.4 seconds B. 0.6 seconds C. 0.8 seconds D. 1.0 second
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
am saying A but not sure or B
Compassionate
  • Compassionate
Hi, What would you define as, "Hang time."
anonymous
  • anonymous
time in the air

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Compassionate
  • Compassionate
So you know it travels at 10 ft/s You're given the formula h=-16t^2+10t What do you think you should do? HINT: The Quadratic Formula
anonymous
  • anonymous
IT has to be A
anonymous
  • anonymous
we calculate the time when h=0 i.e.,initially position and again when it comes on the ground. \[-16 t^2+10t=0,-2t \left( 8t-5 \right)=0\] either -2t=0 \[\implies t=0\] it gives initial time. or 8 t-5=0 \[t=\frac{ 5 }{ 8 }=0.625\] it gives final time. so it is in air ?

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