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anonymous
 one year ago
If cos theta = 5/13 and sin theta less than 0, what is tan theta?
anonymous
 one year ago
If cos theta = 5/13 and sin theta less than 0, what is tan theta?

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kittiwitti1
 one year ago
Best ResponseYou've already chosen the best response.0Is this what you're asking?\[\text{If }\cos\theta=\frac{5}{13}\text{ and }\sin\theta\lt0\text{, what is }\tan\theta?\]

kittiwitti1
 one year ago
Best ResponseYou've already chosen the best response.0Okay. First question you ask yourself: which quadrant has negative sines?

kittiwitti1
 one year ago
Best ResponseYou've already chosen the best response.0(aka negative "yvalues")

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay um 1 and 3 i think

kittiwitti1
 one year ago
Best ResponseYou've already chosen the best response.0Q1 is wrong, but you got Q3. Here's a reference image: http://www.chilimath.com/algebra/intro/point/images/quadrants_1.gif

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i couldnt think without looking so 3 and 4

kittiwitti1
 one year ago
Best ResponseYou've already chosen the best response.0But good work nonetheless. =) So now you have narrowed down your options to Q3 and Q4.

kittiwitti1
 one year ago
Best ResponseYou've already chosen the best response.0(sorry I need to find some scratch paper)

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2hint angle theta has to belongs to the III quadrant: dw:1435382600490:dw

kittiwitti1
 one year ago
Best ResponseYou've already chosen the best response.0Okay yeah what she said. So now we have a triangle in QIIIdw:1435382756655:dw

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2hint: \[\Large \sin \theta =  \sqrt {1  {{\left( {  \frac{5}{{13}}} \right)}^2}} = ...\]

kittiwitti1
 one year ago
Best ResponseYou've already chosen the best response.0lol I don't remember learning that in high school x_x

kittiwitti1
 one year ago
Best ResponseYou've already chosen the best response.0I thought there were two answers to this question tbh

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2it is the value of the associated function sin(\theta): \[\Large \sin \theta =  \sqrt {1  {{\left( {\cos \theta } \right)}^2}} \]

kittiwitti1
 one year ago
Best ResponseYou've already chosen the best response.0On second thought I think I'll let her explain because I just confused myself. :v

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0answer choices a. 12/5 b.13/5 c.12/5 d.square root of 194/5

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2hint: next steps: \[\Large \begin{gathered} \sin \theta =  \sqrt {1  {{\left( {  \frac{5}{{13}}} \right)}^2}} =  \sqrt {1  \frac{{25}}{{169}}} = \hfill \\ \hfill \\ =  \sqrt {\frac{{144}}{{169}}} =  \frac{{12}}{{13}} \hfill \\ \end{gathered} \]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0in case you guys don't get where he got that radical from, he's using the identity \(\sin^2\theta+\cos^2\theta=1\)

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2hint: so we can write: \[\Large \tan \theta = \frac{{\sin \theta }}{{\cos \theta }} = \frac{{  \frac{{12}}{{13}}}}{{  \frac{5}{{13}}}} = ...?\]

kittiwitti1
 one year ago
Best ResponseYou've already chosen the best response.0Oh I mostly get it but I was multitasking sorry xD so I decided to leave the problem to someone who could focus their whole effort into helping

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2please, complete my computation above @brandijeannnn
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