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anonymous

  • one year ago

How can i solve this KIND OF VALUE (〖-i)〗^i

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  1. welshfella
    • one year ago
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    we might write -i as cos 3pi/2 + i sin 3pi/2 = e^(i 3pi/2) so -i^i = [e^(i 3pi/2)]^i = e^ -3pi/2 = approx 0.00898

  2. welshfella
    • one year ago
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    a rational number Surprising result.

  3. Jenma
    • one year ago
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    is that imaginary number?

  4. welshfella
    • one year ago
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    well i is but 00898 isn't

  5. Jenma
    • one year ago
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    oh ok, i thought it was just an imaginary number to the power of i is,,that will be equal to 1.

  6. welshfella
    • one year ago
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    I should have said 0.00898 is a real number - it might not be rational.

  7. welshfella
    • one year ago
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    there are some remarkable results sometimes when you play with complex numbers. the Euler equation is derived from comples numbers also e^i pi = cos pi + i sin pi = -1 + 0i = -1 so e ^ i pi + 1 = 0 This equation unites the 5 most important numbers in mathematics: 0 , 1, pi, e, and i.

  8. anonymous
    • one year ago
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    Thanks DEAR

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