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do you know the rate formula

Yeah. I think it's either A or B not really sure...

yep i agree with trojan

wait

im not sure :/

Give me a second, I am gonna check.

oh okay

So what would the answer be?

agree with trojan A

The catalyst will decreease the energy of activation so as to increease the rate of the reaction

This one?

i have already said about that

I think the transition state is at the top of the curve which is represented by D on the graph.

it's D.

|dw:1435413759932:dw|

Wait, so it's D. A
or C. D ?

Answer is C. D

confusing lol

It isnt

for product to form
collision has to occur

So B,

yep the orientation matters too
but nothing is mentioned about it

Yes, but never in any real reaction will all collision result in a product

oops B lol

I cant tell the difference between A and B they look worded the same

It was A.

That question was strange

How about this one?

I think this is a zero order reaction due to the negative slope/straight line

Im not completely sure im a bit rusty with kinematics

Which of these is correct?

i think it is first order reaction

Yea, it is I was wrong.

I didnt that the it was the ln[X] and not just [X] on the y axis

didnt notice*

yep

So which one is the answer?

need to solve this

@TrojanPoem what do you think?

well guys
i need to go

Sorry to go like this in between :(
all the best vera

cya @rvc

I think i have an Idea on how to solve this

We first say that y=-.0952x+.25 and then we plug in 10 for x and find the cooresponding y value

What did you get when you did that?

nope I dont think that is going to work nm

Water is not counted in the rate constant equation.

What?

Ohh I got C for my answer at first, but now I think I did it wrong /:

@abb0t What did you get?

Well, what does the graph tell you?
Is it zeroth order, first order, second order...

First order right?

Yep. If the graph is linear and has a negative slope, it's first order. Remember that.

I'm not really sure. I just used the one that @sweetburger gave me...

[A] = [A]\(_0\) - kt

I cant tell if the equation should be ln[A]=-kt+ln[A0] or something like [A]=[A0]e^(-kt)

oops, forgot the ln. this is first order.

that subscript function is useful i need to find that

They are both the same. Think of the natural log function, but you can use either.

I gtg. But i've clarified a lot. I'm sure sweetburger can take it from here.

Oh boy

Thanks @abb0t

Oh i think I may have figured it out

Okay...

Anything?

Okay, if I were to guess, which should I choose?

I dont know how much time you have to complete this, but I could try this one more way

No that didnt work either

Idk maybe try A, but I really dont know

OH ITS B

I just needed to do this i think .25/-.0952 = -2.62sec^-1

It was A!!

Very sorry :/

Im clueless @abb0t