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vera_ewing
 one year ago
chemistry question
vera_ewing
 one year ago
chemistry question

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rvc
 one year ago
Best ResponseYou've already chosen the best response.3do you know the rate formula

vera_ewing
 one year ago
Best ResponseYou've already chosen the best response.0Yeah. I think it's either A or B not really sure...

TrojanPoem
 one year ago
Best ResponseYou've already chosen the best response.1I think this question is chemical equilibrium related. I think (A) as Water is not counted but oxygen water is counted.

TrojanPoem
 one year ago
Best ResponseYou've already chosen the best response.1Give me a second, I am gonna check.

TrojanPoem
 one year ago
Best ResponseYou've already chosen the best response.1I found this : A firstorder reaction is a reaction that proceeds at a rate that depends linearly on only one reactant concentration. [So H2o2 only]

vera_ewing
 one year ago
Best ResponseYou've already chosen the best response.0So what would the answer be?

vera_ewing
 one year ago
Best ResponseYou've already chosen the best response.0What happens to the energy of the transition state when a catalyst is used? A. The energy increases. B. The energy decreases. C. The energy does not change. D. The energy varies during the catalyzed reaction.

rvc
 one year ago
Best ResponseYou've already chosen the best response.3The catalyst will decreease the energy of activation so as to increease the rate of the reaction

rvc
 one year ago
Best ResponseYou've already chosen the best response.3i have already said about that

sweetburger
 one year ago
Best ResponseYou've already chosen the best response.0I think the transition state is at the top of the curve which is represented by D on the graph.

vera_ewing
 one year ago
Best ResponseYou've already chosen the best response.0Wait, so it's D. A or C. D ?

vera_ewing
 one year ago
Best ResponseYou've already chosen the best response.0Which of the following statements is true if HI is formed in the following reaction? H2(g) + I2(g) → 2HI(g) A. Some of the collisions of the reactants have enough energy to overcome the activation energy. B. Some of the collisions between reactants have enough energy to overcome the reaction mechanism. C. There are no collisions between the reactants in the reaction. D. All of the collisions between reactants have enough energy to overcome the activation energy.

rvc
 one year ago
Best ResponseYou've already chosen the best response.3for product to form collision has to occur

sweetburger
 one year ago
Best ResponseYou've already chosen the best response.0In collision theory not all of the colliosions will result in a creation of a product. Only if the collision has the proper orientation and energy will it create a product.

rvc
 one year ago
Best ResponseYou've already chosen the best response.3yep the orientation matters too but nothing is mentioned about it

sweetburger
 one year ago
Best ResponseYou've already chosen the best response.0Yes, but never in any real reaction will all collision result in a product

sweetburger
 one year ago
Best ResponseYou've already chosen the best response.0I cant tell the difference between A and B they look worded the same

sweetburger
 one year ago
Best ResponseYou've already chosen the best response.0That question was strange

vera_ewing
 one year ago
Best ResponseYou've already chosen the best response.0How about this one?

sweetburger
 one year ago
Best ResponseYou've already chosen the best response.0I think this is a zero order reaction due to the negative slope/straight line

sweetburger
 one year ago
Best ResponseYou've already chosen the best response.0Im not completely sure im a bit rusty with kinematics

vera_ewing
 one year ago
Best ResponseYou've already chosen the best response.0Which of these is correct?

rvc
 one year ago
Best ResponseYou've already chosen the best response.3i think it is first order reaction

sweetburger
 one year ago
Best ResponseYou've already chosen the best response.0Yea, it is I was wrong.

sweetburger
 one year ago
Best ResponseYou've already chosen the best response.0I didnt that the it was the ln[X] and not just [X] on the y axis

vera_ewing
 one year ago
Best ResponseYou've already chosen the best response.0So which one is the answer?

rvc
 one year ago
Best ResponseYou've already chosen the best response.3@TrojanPoem what do you think?

rvc
 one year ago
Best ResponseYou've already chosen the best response.3Sorry to go like this in between :( all the best vera

sweetburger
 one year ago
Best ResponseYou've already chosen the best response.0I think i have an Idea on how to solve this

sweetburger
 one year ago
Best ResponseYou've already chosen the best response.0We first say that y=.0952x+.25 and then we plug in 10 for x and find the cooresponding y value

vera_ewing
 one year ago
Best ResponseYou've already chosen the best response.0What did you get when you did that?

sweetburger
 one year ago
Best ResponseYou've already chosen the best response.0nope I dont think that is going to work nm

abb0t
 one year ago
Best ResponseYou've already chosen the best response.0Water is not counted in the rate constant equation.

abb0t
 one year ago
Best ResponseYou've already chosen the best response.0Understand that a catalyst does \(\sf \color{red}{NOT}\) lower or decrease the energy of activation of a reaction, rather it finds a \(new\) pathway so that it expends less energy, and proceeds faster and consequently, lowering the requirement of the transition energy for that same reaction to proceed.

abb0t
 one year ago
Best ResponseYou've already chosen the best response.0For instance, you have: \(\sf \color{blue}{A \rightarrow D} \) without a catalyst, it might require 100 kj/mol but with the catalyst, it finds a new pathway that may only require 15 kj/mol.

vera_ewing
 one year ago
Best ResponseYou've already chosen the best response.0Ohh I got C for my answer at first, but now I think I did it wrong /:

vera_ewing
 one year ago
Best ResponseYou've already chosen the best response.0@abb0t What did you get?

sweetburger
 one year ago
Best ResponseYou've already chosen the best response.0@abb0t Could you help out with this question http://assets.openstudy.com/updates/attachments/558ea82ee4b0058b2bb701f0vera_ewing1435414099554screenshot20150627at10.08.08am.png

abb0t
 one year ago
Best ResponseYou've already chosen the best response.0Well, what does the graph tell you? Is it zeroth order, first order, second order...

abb0t
 one year ago
Best ResponseYou've already chosen the best response.0Yep. If the graph is linear and has a negative slope, it's first order. Remember that.

abb0t
 one year ago
Best ResponseYou've already chosen the best response.0So, what equation should you use? Since it's linear, it will be something along the lines of: y = mx+ b which is the equation of a line.

vera_ewing
 one year ago
Best ResponseYou've already chosen the best response.0I'm not really sure. I just used the one that @sweetburger gave me...

sweetburger
 one year ago
Best ResponseYou've already chosen the best response.0I cant tell if the equation should be ln[A]=kt+ln[A0] or something like [A]=[A0]e^(kt)

abb0t
 one year ago
Best ResponseYou've already chosen the best response.0oops, forgot the ln. this is first order.

sweetburger
 one year ago
Best ResponseYou've already chosen the best response.0that subscript function is useful i need to find that

abb0t
 one year ago
Best ResponseYou've already chosen the best response.0They are both the same. Think of the natural log function, but you can use either.

abb0t
 one year ago
Best ResponseYou've already chosen the best response.0I gtg. But i've clarified a lot. I'm sure sweetburger can take it from here.

sweetburger
 one year ago
Best ResponseYou've already chosen the best response.0Oh i think I may have figured it out

sweetburger
 one year ago
Best ResponseYou've already chosen the best response.0I literally just need to find another concentration value at a specific time and this would be so easy.

sweetburger
 one year ago
Best ResponseYou've already chosen the best response.0Nope, closest to any of the answer i have gotten is like .018s^1. I'm sorry, but this question is just escaping me.

vera_ewing
 one year ago
Best ResponseYou've already chosen the best response.0Okay, if I were to guess, which should I choose?

sweetburger
 one year ago
Best ResponseYou've already chosen the best response.0I dont know how much time you have to complete this, but I could try this one more way

sweetburger
 one year ago
Best ResponseYou've already chosen the best response.0No that didnt work either

sweetburger
 one year ago
Best ResponseYou've already chosen the best response.0Idk maybe try A, but I really dont know

sweetburger
 one year ago
Best ResponseYou've already chosen the best response.0I just needed to do this i think .25/.0952 = 2.62sec^1

abb0t
 one year ago
Best ResponseYou've already chosen the best response.0C'mon guys, that's why you have the graph! for a firstorder reaction, it gives you what you have there, a straight line with the slope of the line equal to \(\sf \color{red}{k}\) If you know that your slope is k, plug it in, and then substitute your value into the proper equation to solve for the rate of reaction is the change in concentration of the reactants or the change in concentration of the products per unit time. Which means, you're looking for \(\sf \color{red}{\frac{M}{s}}\)

sweetburger
 one year ago
Best ResponseYou've already chosen the best response.0Im clueless @abb0t
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