mathmath333
  • mathmath333
Graphical functions
Mathematics
  • Stacey Warren - Expert brainly.com
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schrodinger
  • schrodinger
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mathmath333
  • mathmath333
\(\large \color{black}{\begin{align} &a.) \ f(x)=-f(x) \hspace{.33em}\\~\\ &b.) \ f(x)=f(-x) \hspace{.33em}\\~\\ &c.) \ \normalsize \text{neither even nor odd function} \hspace{.33em}\\~\\ &d.) \ f(x)\ \normalsize \text{doesn't exist at atleast one point of the domain.} \hspace{.33em}\\~\\ \end{align}}\)
mathmath333
  • mathmath333
|dw:1435416879315:dw|
amoodarya
  • amoodarya
it is not ? \[f(x)=cotan(x)\] because of vertical retricemptotes ,and roots

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mathmath333
  • mathmath333
i don't have any clue about the equation of the graph
amoodarya
  • amoodarya
vertical asymptote ! i had a mistake if f(x)=cotan(x) \[f(-x)=\cot(-x)=\frac{\cos(-x)}{\sin(-x)}=\frac{\cos(x)}{-\sin(x)}=-\cot(x) =-f(x)\]
mathmath333
  • mathmath333
|dw:1435417311725:dw|
amoodarya
  • amoodarya
it looks : the roots have a symmetry I think they show roots ,nothing more if they are part of figure , this is not a function
amoodarya
  • amoodarya
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phi
  • phi
btw, choice a) f(x)=-f(x) probably should read f(x) = - f(-x) f(x)= -f(x) would mean y=-y which is only true for y=0
mathmath333
  • mathmath333
m confused is the answer d.)
amoodarya
  • amoodarya
domain of this function has not 1 point out R in your picture ,\[D_f=\mathbb{R} -\left\{ 0,a,b \right\}\]
mathmath333
  • mathmath333
what is a and b
alekos
  • alekos
i'd say the lines just indicate zero crossing points and vertical asymptotes
triciaal
  • triciaal
From a textbook this is the graph of y = cot x the domain of the secant function is the set of all real numbers except those of the form 1/2 pi + n pi, and the function is continuous on its domain. Because with limit sec x = +/- angle, the graph of the secant function has the lines x = 1/2 pi + nr as vertical asymptotes. There is no intersection of the graph with the x axis because sec x is never zero. The secant function is even because
triciaal
  • triciaal
|dw:1435422150442:dw|
mathmath333
  • mathmath333
in my book answer is d.)
triciaal
  • triciaal
and so the graph of the secant function is symmetric with respect to the y axis.
amoodarya
  • amoodarya
|dw:1435418650098:dw|
amoodarya
  • amoodarya
I thin\[\pm\pi\]k a, b are
triciaal
  • triciaal
I can see D because it says sec x is never zero no intersection with x axis
mathmath333
  • mathmath333
ok so its d.) , thanks.
mathmath333
  • mathmath333
|dw:1435419073815:dw| what about this graph
mathmath333
  • mathmath333
is this even
amoodarya
  • amoodarya
yes , function you draw is even
mathmath333
  • mathmath333
|dw:1435419275045:dw|
mathmath333
  • mathmath333
this graph is even too ?
amoodarya
  • amoodarya
yes I think you tried to sketch sec(x)
mathmath333
  • mathmath333
this is even ?
mathmath333
  • mathmath333
it was not given it is sec x .
amoodarya
  • amoodarya
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mathmath333
  • mathmath333
ok thnx
mathmath333
  • mathmath333
what is that dotted line btw
amoodarya
  • amoodarya
vertical asymptote
amoodarya
  • amoodarya
do you know vertical asymptote ?
mathmath333
  • mathmath333
yes
mathmath333
  • mathmath333
not in graph
amoodarya
  • amoodarya
usually when denominator goes to zero , function go to infinity (usually)
amoodarya
  • amoodarya
now , whats your choice ?
mathmath333
  • mathmath333
choice ?
amoodarya
  • amoodarya
a,b,c,d ?
mathmath333
  • mathmath333
b.)
mathmath333
  • mathmath333
i mean it is even function
amoodarya
  • amoodarya
it is not an even function in your picture I see a odd function

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