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mathmath333
 one year ago
Graphical functions
mathmath333
 one year ago
Graphical functions

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mathmath333
 one year ago
Best ResponseYou've already chosen the best response.1\(\large \color{black}{\begin{align} &a.) \ f(x)=f(x) \hspace{.33em}\\~\\ &b.) \ f(x)=f(x) \hspace{.33em}\\~\\ &c.) \ \normalsize \text{neither even nor odd function} \hspace{.33em}\\~\\ &d.) \ f(x)\ \normalsize \text{doesn't exist at atleast one point of the domain.} \hspace{.33em}\\~\\ \end{align}}\)

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.1dw:1435416879315:dw

amoodarya
 one year ago
Best ResponseYou've already chosen the best response.1it is not ? \[f(x)=cotan(x)\] because of vertical retricemptotes ,and roots

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.1i don't have any clue about the equation of the graph

amoodarya
 one year ago
Best ResponseYou've already chosen the best response.1vertical asymptote ! i had a mistake if f(x)=cotan(x) \[f(x)=\cot(x)=\frac{\cos(x)}{\sin(x)}=\frac{\cos(x)}{\sin(x)}=\cot(x) =f(x)\]

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.1dw:1435417311725:dw

amoodarya
 one year ago
Best ResponseYou've already chosen the best response.1it looks : the roots have a symmetry I think they show roots ,nothing more if they are part of figure , this is not a function

phi
 one year ago
Best ResponseYou've already chosen the best response.0btw, choice a) f(x)=f(x) probably should read f(x) =  f(x) f(x)= f(x) would mean y=y which is only true for y=0

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.1m confused is the answer d.)

amoodarya
 one year ago
Best ResponseYou've already chosen the best response.1domain of this function has not 1 point out R in your picture ,\[D_f=\mathbb{R} \left\{ 0,a,b \right\}\]

alekos
 one year ago
Best ResponseYou've already chosen the best response.0i'd say the lines just indicate zero crossing points and vertical asymptotes

triciaal
 one year ago
Best ResponseYou've already chosen the best response.1From a textbook this is the graph of y = cot x the domain of the secant function is the set of all real numbers except those of the form 1/2 pi + n pi, and the function is continuous on its domain. Because with limit sec x = +/ angle, the graph of the secant function has the lines x = 1/2 pi + nr as vertical asymptotes. There is no intersection of the graph with the x axis because sec x is never zero. The secant function is even because

triciaal
 one year ago
Best ResponseYou've already chosen the best response.1dw:1435422150442:dw

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.1in my book answer is d.)

triciaal
 one year ago
Best ResponseYou've already chosen the best response.1and so the graph of the secant function is symmetric with respect to the y axis.

amoodarya
 one year ago
Best ResponseYou've already chosen the best response.1dw:1435418650098:dw

amoodarya
 one year ago
Best ResponseYou've already chosen the best response.1I thin\[\pm\pi\]k a, b are

triciaal
 one year ago
Best ResponseYou've already chosen the best response.1I can see D because it says sec x is never zero no intersection with x axis

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.1ok so its d.) , thanks.

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.1dw:1435419073815:dw what about this graph

amoodarya
 one year ago
Best ResponseYou've already chosen the best response.1yes , function you draw is even

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.1dw:1435419275045:dw

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.1this graph is even too ?

amoodarya
 one year ago
Best ResponseYou've already chosen the best response.1yes I think you tried to sketch sec(x)

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.1it was not given it is sec x .

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.1what is that dotted line btw

amoodarya
 one year ago
Best ResponseYou've already chosen the best response.1do you know vertical asymptote ?

amoodarya
 one year ago
Best ResponseYou've already chosen the best response.1usually when denominator goes to zero , function go to infinity (usually)

amoodarya
 one year ago
Best ResponseYou've already chosen the best response.1now , whats your choice ?

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.1i mean it is even function

amoodarya
 one year ago
Best ResponseYou've already chosen the best response.1it is not an even function in your picture I see a odd function
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