anonymous
  • anonymous
The figure below shows a shaded region and a nonshaded region. Angles in the figure that appear to be right angles are right angles.
Mathematics
chestercat
  • chestercat
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anonymous
  • anonymous
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anonymous
  • anonymous
What is the area, in square feet, of the shaded region? What is the area, in square feet, of the nonshaded region?
anonymous
  • anonymous

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anonymous
  • anonymous
anyone???????????? ill give a medall
anonymous
  • anonymous
anonymous
  • anonymous
anonymous
  • anonymous
paki
  • paki
@CausticSyndicalist please help....
Kash_TheSmartGuy
  • Kash_TheSmartGuy
I would, probably divide the shaded area into a rectangle and a trapezoid
Michele_Laino
  • Michele_Laino
we can see the shaded region as composed by the subsequent geometrical shapes: |dw:1435426492812:dw|
Kash_TheSmartGuy
  • Kash_TheSmartGuy
Then, you need to find the area of the trapezoid and the rectangle and add them both up. The answer is area for the shaded region.
Kash_TheSmartGuy
  • Kash_TheSmartGuy
Area of a trapezoid: A=[(a+b)/2]h
Kash_TheSmartGuy
  • Kash_TheSmartGuy
Area of a Rectangle: L*B
Kash_TheSmartGuy
  • Kash_TheSmartGuy
Fill in the values.
Kash_TheSmartGuy
  • Kash_TheSmartGuy
Try typing: "Area of Trapezoid" on google. There you will find a calculator, you can fill the values in there!
anonymous
  • anonymous
what arwe the values
anonymous
  • anonymous
like base base ansd hieght
Kash_TheSmartGuy
  • Kash_TheSmartGuy
1 for a, 4 for b, 10 for h.
Kash_TheSmartGuy
  • Kash_TheSmartGuy
The answer is 25 ft for the area of the trapezoid. Then, for the area of a rectangle: 8*2=16. Add: 25+16=Your Answer for no.1
anonymous
  • anonymous
so 41
Kash_TheSmartGuy
  • Kash_TheSmartGuy
Is that in the options?
anonymous
  • anonymous
Yes it is and okay do u know number 2 by any chance
Kash_TheSmartGuy
  • Kash_TheSmartGuy
I think we need to divide it into 1 trapezoid and 3 rectangles
anonymous
  • anonymous
Yeah i do too i just get confused on the math part
Kash_TheSmartGuy
  • Kash_TheSmartGuy
So do it, find the area for all figures, then add the area up and there is your answer for no.2!

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