anonymous
  • anonymous
Which is the solution of the system? A. (-4,2) B. (-3,1) C. (-3,-5) D. (4,-6)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
|dw:1435437755769:dw|
anonymous
  • anonymous
do i use distributive property???
Astrophysics
  • Astrophysics
I don't really know what your question is asking

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anonymous
  • anonymous
yeah nvm i understand it now that i really look at it..its all good
Astrophysics
  • Astrophysics
\[\frac{ (x+y) }{ (2x-3y) } = -\frac{ 2 }{ 9 }\] is the problem this?
Astrophysics
  • Astrophysics
Can you just take a picture of it and upload it
anonymous
  • anonymous
Astrophysics
  • Astrophysics
Oh, that makes sense, they are two different equations right?
Astrophysics
  • Astrophysics
Yeah!
anonymous
  • anonymous
so basically i just use distributive property?
Astrophysics
  • Astrophysics
Ok so you have two equations, \[x+y=-2\] \[2x-3y=-9\] No not quite, so does it ask for any methods, like elimination, substitution, matrices?
anonymous
  • anonymous
it asks what the solution is
Astrophysics
  • Astrophysics
Ok, we can use any method then
anonymous
  • anonymous
im gonna give you a medal just cuz youve been the most help ive had since ive gotten on here
Astrophysics
  • Astrophysics
Lets use substitution, so to do this problem, we want to isolate one of the variables in one of the equations and plug it into the second equation, that will help us find the x value and then we can go back and find the y value. We could also take your options in to our advantage and do it the lazy way but I don't think you will learn that way.
Astrophysics
  • Astrophysics
Ok I think drawing it out will make more sense, first you want to label the equations
anonymous
  • anonymous
Did you read what i said?
Astrophysics
  • Astrophysics
|dw:1435438438884:dw| Hey, yes I did thanks :) So lets do this problem now, pick one of the equations and one of the variables to isolate in that equation.
anonymous
  • anonymous
2
Astrophysics
  • Astrophysics
Haha, actually lets pick one as it's a bit more simple to deal with it
anonymous
  • anonymous
ok 1 it is
Astrophysics
  • Astrophysics
Now lets say we solve for x
Astrophysics
  • Astrophysics
|dw:1435438607278:dw| so far so good?
anonymous
  • anonymous
yerp
Astrophysics
  • Astrophysics
Ok great, now we want to take this expression and plug it into the second equation, as such |dw:1435438692346:dw| notice how we have removed x from the equation now we can simply solve for the y!
Astrophysics
  • Astrophysics
Could you try solving for y? Don't worry about making mistakes long as you're attempting that's awesome.
anonymous
  • anonymous
|dw:1435438790521:dw|
anonymous
  • anonymous
is that right???????
Astrophysics
  • Astrophysics
Yes, it's being multiplied so you have to distribute
anonymous
  • anonymous
|dw:1435438885781:dw|
anonymous
  • anonymous
ill brb i gotta get something..it might be a few minutes...plzzz wait
Astrophysics
  • Astrophysics
Not quite, |dw:1435438982368:dw| does that make sense?
anonymous
  • anonymous
yes sorry for the wait lol
Astrophysics
  • Astrophysics
It's ok
Astrophysics
  • Astrophysics
Now you want to simplify it, collect like terms and solve for y
anonymous
  • anonymous
would it be 2-3y or -2-3y?????
Astrophysics
  • Astrophysics
I'm not sure what you mean but |dw:1435439329301:dw| so y will be?
anonymous
  • anonymous
it is -2-3y i got -9=-9
anonymous
  • anonymous
whhhaaaatt
anonymous
  • anonymous
ooohhhi did that all wrong i got that now lmao
Astrophysics
  • Astrophysics
Ok :), now just solve for y? One step needed
anonymous
  • anonymous
soo the only answer with y=1 is b...would that be the answer?
Astrophysics
  • Astrophysics
Yes, y = 1, but you should make sure to check with x just in case you did not make any mistakes, lets take equation 1 and plug y in it.
Astrophysics
  • Astrophysics
|dw:1435439549600:dw| so our solution is (-3,1) yup!
anonymous
  • anonymous
yayyy its right..thank you so much.. =^w^=
Astrophysics
  • Astrophysics
Np :)

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