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\[y=3\cos^3(\sin^{-1} \sqrt[3]{x/3})\]

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It has to simplify to y = ?

I dont know how the \[\sqrt[3]{x}\] would be squared and what that would come out to

well ? would be \[\sqrt{9-x ^{2/3}}\]

since we can't find x

oh. that cubed (to lazy to type it)

what's your question?

cos^3?

Can you simplify this
\[\Large \cos^2t=\left(\frac{\sqrt{9-x^{2/3}}}{3}\right)^2\]

\[\frac{ 9-x ^{2/3} }{ 9 }\]

very good