A balloon has a circumference of 28 in. Use the circumference to approximate the surface area of the balloon to the nearest square inch. 784 in2 2,463 in2 998 in2 250 in2

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A balloon has a circumference of 28 in. Use the circumference to approximate the surface area of the balloon to the nearest square inch. 784 in2 2,463 in2 998 in2 250 in2

Mathematics
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What is the slant height of the pyramid to the nearest tenth? 19.0 mm 12.5 mm 15.5 mm 13.9 mm
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Using Euler’s Formula (F + V = E + 2), find the number of faces. Vertices: 16 Edges: 37 Faces: ?
F=23 i think

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Other answers:

for the Euler's formula one
ok thanks!
for the balloon problem circumference = 2*pi*r where r is the radius of the balloon we can solve for r by substituting 28 for the circumference 28 = 2*pi*r r = 14/pi surface area of a sphere = 4*pi*r^2 since r = 14/pi, we can plug in 14/pi into the surface area equation and solve for surface area
so do i do 2*3.14*14?
hm, not quite, we want to solve for r first 28 = 2*pi*r we divide both sides by 2 pi, giving us 14/pi = r then we use this value of r for the surface area equation
i got 87 23/25?
|dw:1435442689088:dw|
can you show me how you got that answer?
14/3.14 = 4 72/157
is that right?
well, yes, that would be the value of r (let's convert to decimals in this case, it'll make it a bit easier for us later on) r = 14/3.14 = 4.46
ok
then we can use this value of r for the surface area equation surface area = 4*pi*r^2 = 4*3.14*(4.46)^2 = 249.8, which rounds to 250
oh okay thanks !
could u please help me with my second question above?
im not sure on this one either :/ What is the surface area of the pyramid to the nearest whole number? 30 cm2 25 cm2 60 cm2 85 cm2
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let's focus on the slant height one first (the one you posted earlier) the height of the pyramid is 12 and the its base is a square with side lengths of 7 if you look at the triangle inside the pyramid, you can see that it's a right triangle with legs 12 and 3.5 (since 7/2 = 3.5) the slant height (the hypotenuse) can be found using the Pythagorean theorem
|dw:1435443114081:dw|
whats the pythagorean theorem?
|dw:1435443244024:dw|
oh a^2+b^2=c^2?
yeah
i got 156 1/4
remember to take the square root at the end
244414 1/16?
square root, not square
|dw:1435443406104:dw|
\[\sqrt{?} this on a an\]
yes
on a and b and c?
the pythagorean theorem tells us (slant height)^2 = 12^2 + 3.5^2 = 156.25 to find slant height, we take the square root of both sides
220.9708691?
square root slant height^2 = 156.25 slant height = square root of 156.25
12 1/2?
yup, you got it, do you understand what we did?
yes! thank you! and now can we do my next question ?
alright, it wants the surface area of the pyramid, which means we need to find the area of each of the 4 triangular faces + the area of the base each of the triangles has base = 5 and height = 6 the area of a triangle can be found using the formula: area = (1/2)(base)(height) so the combined area of all the triangles is 4*(1/2)(base)(height) next, we want to find the area of the base, which is a square with sides 5. the area of a square can be found using area = s^2 to find the final answer, add the area of the 4 triangles + area of the square
so putting everything together base = 5 height = 6 surface area = 4*(1/2)(base)(height) + (base)^2
160?
but thats not on my answers
please check your calculations again
surface area = 4*(1/2)(6)(5) + (5)^2
85? so i was right then because i already have that answer checked?
yup, 85 is what I got too
What is the surface area of the right prism? 540 in2 486 in2 648 in2 972 in2
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thanks!
surface area of a prism = 2*L*W + 2*W*H + 2*H*L H = 18 W = 6 L = 9
*rectangular prism
648(:
What is the volume of the cone to the nearest tenth? 829.4 m3 1,520.5 m3 552.9 m3 1,244.1 m3
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i think its a
(assuming that the radius is 11, kinda ambiguous from the diagram) volume of cone = (1/3)(pi)*h*(r^2) r = 11 h = 12
What is the surface area of the pyramid to the nearest whole number? 96 cm2 132 cm2 72 cm2 156 cm2
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a is incorrect, please try my formula
i got 1519 19/25
which is closest to answer b (probably because of rounding)
19/25 as a decimal is 0.760
thanku
and for the last one, it's asking for the surface area of the pyramid. the last problem you posted is very similar to the third problem you posted (surface area of a pyramid), just with different numbers. perhaps you look at my work and solve it on your own? :)
helpful reminder: surface area of pyramid = area of 4 triangles + area of square base
so (1/3)*3.14*8*(6^2) = 301 11/25
wrong formula. area of triangle = (1/2)(base)(height) area of square = (base)^2
so 24 and 36
right, and there are 4 triangles and 1 square so surface area = 4*area of triangle + area of squrae
132
great
do you know anything about this figure? What is the volume of the composite figure? 192 ft3 76 ft3 152 ft3 96 ft3
hint: it's 2 prisms put together|dw:1435446620974:dw|
find the volume of prism A and add to the volume of prism B volume = L*W*H volume of A = (4)(2)(8) volume of B = (2)(2)3)
do u know what part would be length?
oh nvrm
|dw:1435446845195:dw|
A= 64 B= 12
right, so keep going
what do i do next?
64+12= 76
right
ok thanku
What is the volume of the square pyramid? Round to the nearest tenth. 40.0 cm3 480.0 cm3 147.3 cm3 720.0 cm3
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volume of square pyramid = (1/3)(L)(W)(H)
480?
great
wouldnt this be rectangle? Describe the cross section of the rectangular prism. rectangle hexagon trapezoid triangle
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yup, good job
thank you for all your time and effort to help me!(:
no problem, I'm glad I was able to help

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