mckenzieandjesus
  • mckenzieandjesus
A balloon has a circumference of 28 in. Use the circumference to approximate the surface area of the balloon to the nearest square inch. 784 in2 2,463 in2 998 in2 250 in2
Mathematics
  • Stacey Warren - Expert brainly.com
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jamiebookeater
  • jamiebookeater
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mckenzieandjesus
  • mckenzieandjesus
What is the slant height of the pyramid to the nearest tenth? 19.0 mm 12.5 mm 15.5 mm 13.9 mm
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mckenzieandjesus
  • mckenzieandjesus
Using Euler’s Formula (F + V = E + 2), find the number of faces. Vertices: 16 Edges: 37 Faces: ?
anonymous
  • anonymous
F=23 i think

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anonymous
  • anonymous
for the Euler's formula one
mckenzieandjesus
  • mckenzieandjesus
ok thanks!
mckenzieandjesus
  • mckenzieandjesus
@jim_thompson5910
Vocaloid
  • Vocaloid
for the balloon problem circumference = 2*pi*r where r is the radius of the balloon we can solve for r by substituting 28 for the circumference 28 = 2*pi*r r = 14/pi surface area of a sphere = 4*pi*r^2 since r = 14/pi, we can plug in 14/pi into the surface area equation and solve for surface area
mckenzieandjesus
  • mckenzieandjesus
so do i do 2*3.14*14?
Vocaloid
  • Vocaloid
hm, not quite, we want to solve for r first 28 = 2*pi*r we divide both sides by 2 pi, giving us 14/pi = r then we use this value of r for the surface area equation
mckenzieandjesus
  • mckenzieandjesus
i got 87 23/25?
Vocaloid
  • Vocaloid
|dw:1435442689088:dw|
Vocaloid
  • Vocaloid
can you show me how you got that answer?
mckenzieandjesus
  • mckenzieandjesus
14/3.14 = 4 72/157
mckenzieandjesus
  • mckenzieandjesus
is that right?
Vocaloid
  • Vocaloid
well, yes, that would be the value of r (let's convert to decimals in this case, it'll make it a bit easier for us later on) r = 14/3.14 = 4.46
mckenzieandjesus
  • mckenzieandjesus
ok
Vocaloid
  • Vocaloid
then we can use this value of r for the surface area equation surface area = 4*pi*r^2 = 4*3.14*(4.46)^2 = 249.8, which rounds to 250
mckenzieandjesus
  • mckenzieandjesus
oh okay thanks !
mckenzieandjesus
  • mckenzieandjesus
could u please help me with my second question above?
mckenzieandjesus
  • mckenzieandjesus
im not sure on this one either :/ What is the surface area of the pyramid to the nearest whole number? 30 cm2 25 cm2 60 cm2 85 cm2
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Vocaloid
  • Vocaloid
let's focus on the slant height one first (the one you posted earlier) the height of the pyramid is 12 and the its base is a square with side lengths of 7 if you look at the triangle inside the pyramid, you can see that it's a right triangle with legs 12 and 3.5 (since 7/2 = 3.5) the slant height (the hypotenuse) can be found using the Pythagorean theorem
Vocaloid
  • Vocaloid
|dw:1435443114081:dw|
mckenzieandjesus
  • mckenzieandjesus
whats the pythagorean theorem?
Vocaloid
  • Vocaloid
|dw:1435443244024:dw|
mckenzieandjesus
  • mckenzieandjesus
oh a^2+b^2=c^2?
Vocaloid
  • Vocaloid
yeah
mckenzieandjesus
  • mckenzieandjesus
i got 156 1/4
Vocaloid
  • Vocaloid
remember to take the square root at the end
mckenzieandjesus
  • mckenzieandjesus
244414 1/16?
Vocaloid
  • Vocaloid
square root, not square
Vocaloid
  • Vocaloid
|dw:1435443406104:dw|
mckenzieandjesus
  • mckenzieandjesus
\[\sqrt{?} this on a an\]
Vocaloid
  • Vocaloid
yes
mckenzieandjesus
  • mckenzieandjesus
on a and b and c?
Vocaloid
  • Vocaloid
the pythagorean theorem tells us (slant height)^2 = 12^2 + 3.5^2 = 156.25 to find slant height, we take the square root of both sides
mckenzieandjesus
  • mckenzieandjesus
220.9708691?
Vocaloid
  • Vocaloid
square root slant height^2 = 156.25 slant height = square root of 156.25
mckenzieandjesus
  • mckenzieandjesus
12 1/2?
Vocaloid
  • Vocaloid
yup, you got it, do you understand what we did?
mckenzieandjesus
  • mckenzieandjesus
yes! thank you! and now can we do my next question ?
Vocaloid
  • Vocaloid
alright, it wants the surface area of the pyramid, which means we need to find the area of each of the 4 triangular faces + the area of the base each of the triangles has base = 5 and height = 6 the area of a triangle can be found using the formula: area = (1/2)(base)(height) so the combined area of all the triangles is 4*(1/2)(base)(height) next, we want to find the area of the base, which is a square with sides 5. the area of a square can be found using area = s^2 to find the final answer, add the area of the 4 triangles + area of the square
Vocaloid
  • Vocaloid
so putting everything together base = 5 height = 6 surface area = 4*(1/2)(base)(height) + (base)^2
mckenzieandjesus
  • mckenzieandjesus
160?
mckenzieandjesus
  • mckenzieandjesus
but thats not on my answers
Vocaloid
  • Vocaloid
please check your calculations again
Vocaloid
  • Vocaloid
surface area = 4*(1/2)(6)(5) + (5)^2
mckenzieandjesus
  • mckenzieandjesus
85? so i was right then because i already have that answer checked?
Vocaloid
  • Vocaloid
yup, 85 is what I got too
mckenzieandjesus
  • mckenzieandjesus
What is the surface area of the right prism? 540 in2 486 in2 648 in2 972 in2
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mckenzieandjesus
  • mckenzieandjesus
thanks!
Vocaloid
  • Vocaloid
surface area of a prism = 2*L*W + 2*W*H + 2*H*L H = 18 W = 6 L = 9
Vocaloid
  • Vocaloid
*rectangular prism
mckenzieandjesus
  • mckenzieandjesus
648(:
mckenzieandjesus
  • mckenzieandjesus
What is the volume of the cone to the nearest tenth? 829.4 m3 1,520.5 m3 552.9 m3 1,244.1 m3
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mckenzieandjesus
  • mckenzieandjesus
i think its a
Vocaloid
  • Vocaloid
(assuming that the radius is 11, kinda ambiguous from the diagram) volume of cone = (1/3)(pi)*h*(r^2) r = 11 h = 12
mckenzieandjesus
  • mckenzieandjesus
What is the surface area of the pyramid to the nearest whole number? 96 cm2 132 cm2 72 cm2 156 cm2
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Vocaloid
  • Vocaloid
a is incorrect, please try my formula
mckenzieandjesus
  • mckenzieandjesus
i got 1519 19/25
Vocaloid
  • Vocaloid
which is closest to answer b (probably because of rounding)
mckenzieandjesus
  • mckenzieandjesus
19/25 as a decimal is 0.760
mckenzieandjesus
  • mckenzieandjesus
thanku
Vocaloid
  • Vocaloid
and for the last one, it's asking for the surface area of the pyramid. the last problem you posted is very similar to the third problem you posted (surface area of a pyramid), just with different numbers. perhaps you look at my work and solve it on your own? :)
Vocaloid
  • Vocaloid
helpful reminder: surface area of pyramid = area of 4 triangles + area of square base
mckenzieandjesus
  • mckenzieandjesus
so (1/3)*3.14*8*(6^2) = 301 11/25
Vocaloid
  • Vocaloid
wrong formula. area of triangle = (1/2)(base)(height) area of square = (base)^2
mckenzieandjesus
  • mckenzieandjesus
so 24 and 36
Vocaloid
  • Vocaloid
right, and there are 4 triangles and 1 square so surface area = 4*area of triangle + area of squrae
mckenzieandjesus
  • mckenzieandjesus
132
Vocaloid
  • Vocaloid
great
mckenzieandjesus
  • mckenzieandjesus
do you know anything about this figure? What is the volume of the composite figure? 192 ft3 76 ft3 152 ft3 96 ft3
Vocaloid
  • Vocaloid
hint: it's 2 prisms put together|dw:1435446620974:dw|
Vocaloid
  • Vocaloid
find the volume of prism A and add to the volume of prism B volume = L*W*H volume of A = (4)(2)(8) volume of B = (2)(2)3)
mckenzieandjesus
  • mckenzieandjesus
do u know what part would be length?
mckenzieandjesus
  • mckenzieandjesus
oh nvrm
Vocaloid
  • Vocaloid
|dw:1435446845195:dw|
mckenzieandjesus
  • mckenzieandjesus
A= 64 B= 12
Vocaloid
  • Vocaloid
right, so keep going
mckenzieandjesus
  • mckenzieandjesus
what do i do next?
mckenzieandjesus
  • mckenzieandjesus
64+12= 76
Vocaloid
  • Vocaloid
right
mckenzieandjesus
  • mckenzieandjesus
ok thanku
mckenzieandjesus
  • mckenzieandjesus
What is the volume of the square pyramid? Round to the nearest tenth. 40.0 cm3 480.0 cm3 147.3 cm3 720.0 cm3
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Vocaloid
  • Vocaloid
volume of square pyramid = (1/3)(L)(W)(H)
mckenzieandjesus
  • mckenzieandjesus
480?
Vocaloid
  • Vocaloid
great
mckenzieandjesus
  • mckenzieandjesus
wouldnt this be rectangle? Describe the cross section of the rectangular prism. rectangle hexagon trapezoid triangle
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Vocaloid
  • Vocaloid
yup, good job
mckenzieandjesus
  • mckenzieandjesus
thank you for all your time and effort to help me!(:
Vocaloid
  • Vocaloid
no problem, I'm glad I was able to help

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