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anonymous

  • one year ago

Parallelogram JKLM is shown on the coordinate plane below: If parallelogram JKLM is rotated 270° clockwise around the origin, what are the coordinates of the endpoints of the side congruent to side KL in the image parallelogram? (a) K'(−4, −6); L'(3, −3) (b) K'(−6, −4); L'(−3, −3) (c) K'(6, 4); L'(3, 3) (d) K'(−4, 6); L'(−3, −3)

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  1. anonymous
    • one year ago
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  2. LynFran
    • one year ago
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    are u sure u wrote ur options correct im getting k(-4,-6) and L(-3,-3)

  3. anonymous
    • one year ago
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    I copied my options straight from the online worksheet.

  4. LynFran
    • one year ago
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    |dw:1435455752915:dw|

  5. LynFran
    • one year ago
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    @peachpi what do u think can you explain this a little more easier? cause i really dont know how to....

  6. anonymous
    • one year ago
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    I'm not getting those answers either

  7. anonymous
    • one year ago
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    @lynfran I think we both did counterclockwise instead of clockwise

  8. LynFran
    • one year ago
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    maybe but this is counterclockwise |dw:1435457897257:dw|

  9. anonymous
    • one year ago
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    yeah it is, but the question's asking for a clockwise rotation. Is that the same as a 90 deg counterclockwise?

  10. LynFran
    • one year ago
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    true @peachpi

  11. LynFran
    • one year ago
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    and a 90 degree counterclockwise will put the image in the 3rd quadrant ...?@peachpi

  12. anonymous
    • one year ago
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    I was thinking 1st|dw:1435451011488:dw|

  13. anonymous
    • one year ago
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    ok. I looked up this transformation and it's (x,y)→(-y,x). that puts it in the 4th quadrant, which doesn't make sense to me

  14. LynFran
    • one year ago
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    ok let me work this out using matrix and see what will happen

  15. LynFran
    • one year ago
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    |dw:1435458652031:dw|

  16. LynFran
    • one year ago
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    and wow look like the answer is B

  17. anonymous
    • one year ago
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    yep. wow that was more involved that it seemed

  18. LynFran
    • one year ago
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    true @peachpi

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