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anonymous
 one year ago
perform indicated operations. simplify all answers
(2y^27y15/42y^229y5) x (12y^216y+5/7y^236y+5) / (4y^29/49y^21)
HELP PLEASE!
anonymous
 one year ago
perform indicated operations. simplify all answers (2y^27y15/42y^229y5) x (12y^216y+5/7y^236y+5) / (4y^29/49y^21) HELP PLEASE!

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.02\[\frac{ 2y^{2}7y15}{ 42y^{2}29y5}\times \frac{ 12y ^{2}16y+5 }{7y ^{2}36y+5}\div \frac{ 4y ^{2}9 }{49y ^{2}1 }\]

Owlcoffee
 one year ago
Best ResponseYou've already chosen the best response.1First, perform the multiplication, which is just denominator, multiplied denominator and numerator multiplied numerator.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i ll try that! thank you :)

Owlcoffee
 one year ago
Best ResponseYou've already chosen the best response.1After you do that, you can focus on the division.

Loser66
 one year ago
Best ResponseYou've already chosen the best response.1To me, you should try to factor the last term first (both numerator and denominator), then make reciprocal multiplication. I meant: \[.....\div \dfrac{4y^29}{49y^21} = ....*\dfrac{49y^21}{4y^29}\]

Loser66
 one year ago
Best ResponseYou've already chosen the best response.1Now, factor them, it becomes \(....*\dfrac{(7y+1)(7y1)}{(2y3)(2y+3)}\) So that, I am pretty sure that the first 2 terms can have factors such that we can cancel out with the last term. For example, the first term \(\dfrac{2y^27y15}{42y^229y5}=\dfrac{(2y+3)(y5)}{(7y+1)(6y5)}\) Do the same with the middle one, then cancel out to get the answer

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0thank you that is very helpful.. i was thinking about factoring them as well.
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