## anonymous one year ago perform indicated operations. simplify all answers (2y^2-7y-15/42y^2-29y-5) x (12y^2-16y+5/7y^2-36y+5) / (4y^2-9/49y^2-1) HELP PLEASE!

1. anonymous

2$\frac{ 2y^{2}-7y-15}{ 42y^{2}-29y-5}\times \frac{ 12y ^{2}-16y+5 }{7y ^{2}-36y+5}\div \frac{ 4y ^{2}-9 }{49y ^{2}-1 }$

2. Owlcoffee

First, perform the multiplication, which is just denominator, multiplied denominator and numerator multiplied numerator.

3. anonymous

i ll try that! thank you :)

4. Owlcoffee

After you do that, you can focus on the division.

5. Loser66

To me, you should try to factor the last term first (both numerator and denominator), then make reciprocal multiplication. I meant: $.....\div \dfrac{4y^2-9}{49y^2-1} = ....*\dfrac{49y^2-1}{4y^2-9}$

6. Loser66

Now, factor them, it becomes $$....*\dfrac{(7y+1)(7y-1)}{(2y-3)(2y+3)}$$ So that, I am pretty sure that the first 2 terms can have factors such that we can cancel out with the last term. For example, the first term $$\dfrac{2y^2-7y-15}{42y^2-29y-5}=\dfrac{(2y+3)(y-5)}{(7y+1)(6y-5)}$$ Do the same with the middle one, then cancel out to get the answer

7. anonymous

thank you that is very helpful.. i was thinking about factoring them as well.

8. anonymous

thank you!

9. Loser66

np