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anonymous
 one year ago
inverse function property to show that f and g are inverse
f(x)= (x5)/(3x+4) and g(x)= (5+4x)/(13x)
please help!
anonymous
 one year ago
inverse function property to show that f and g are inverse f(x)= (x5)/(3x+4) and g(x)= (5+4x)/(13x) please help!

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I love these questions

Australopithecus
 one year ago
Best ResponseYou've already chosen the best response.3To find the inverse of a function change x to y and change y to x and then solve for y for example the function: f(x) = 3x  1 to find its inverse we switch variables y = 3x  1 switch variables: x = 3y  1 solve for y x + 1 = 3y (x+1)/3 = y therefore the inverse is: \[f^{1}(x) = \frac{(x+1)}{3}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0O shizzzz I think he has the floor

Australopithecus
 one year ago
Best ResponseYou've already chosen the best response.3Note: Not all functions have an inverse, for a function to have an inverse it must be onetoone. To check for this property there is a thing called the horizontal line test see: http://www.mathwords.com/h/horizontal_line_test.htm Essentially for a function to be one to one, every input (x value put into the function) must have a unique output (y value provided as a result of the inputted x value out by the function) for example: A function containing the points: (3, 1) and (4, 1) would not be one to one because there are two x values that give the same output

Australopithecus
 one year ago
Best ResponseYou've already chosen the best response.3sorry for not letting you answer this one Kagome9

Australopithecus
 one year ago
Best ResponseYou've already chosen the best response.3Didnt realize you were going to answer it :)

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.1\[(f\circ g)(x)\\ =f(g(x))\\ =f\left(\frac{5+4x}{13x}\right)\\ =\frac{\left(\frac{5+4x}{13x}\right)5}{3\left(\frac{5+4x}{13x}\right)+4}\\ =\frac{\left(\frac{5+4x}{13x}\right)5}{3\left(\frac{5+4x}{13x}\right)+4}\times\frac{13x}{13x}\\ =\frac{\left(5+4x\right)5(13x)}{3\left({5+4x}\right)+4(13x)}\\ =\frac{5+4x5+15x}{15+12x+412x}\\ =\frac{19x}{19}\\ =x\] \[(f\circ g)(x)=x\iff g= f^{1}\]
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