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Nick88888888
 one year ago
Find the equation in slopeintercept form of the line through points (2, 5) and (6, 15).
How would i do this? Do i use y = mx+b? or what im not sure how to do it
Nick88888888
 one year ago
Find the equation in slopeintercept form of the line through points (2, 5) and (6, 15). How would i do this? Do i use y = mx+b? or what im not sure how to do it

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16shuston
 one year ago
Best ResponseYou've already chosen the best response.0do you know how to figure out the slope?

16shuston
 one year ago
Best ResponseYou've already chosen the best response.0okay so it will be change in y over change in x

Nick88888888
 one year ago
Best ResponseYou've already chosen the best response.0I mean i was asking cause i was trying to search how to do it and some would say y = mx+b and then some would be solving it like this (2,5) and (6, 15) First find slope. (m) (y2y1)/(x2x1) m=(155)/(62)

16shuston
 one year ago
Best ResponseYou've already chosen the best response.0ya you are doing it right so far

16shuston
 one year ago
Best ResponseYou've already chosen the best response.0so then when you find m you use a set o your points to find b.

16shuston
 one year ago
Best ResponseYou've already chosen the best response.0do you want me to show you?

Nick88888888
 one year ago
Best ResponseYou've already chosen the best response.0wait so like this? (2,5) and (6, 15) First find slope. (m) (y2y1)/(x2x1) m=(155)/(62) m=20/4 is the slope now replace x and y terms (y = mx+b) 5=20/4*2+b? is that correct so far?

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0x2 x1 = 6  (2) so it becomes 6 + 2

Nick88888888
 one year ago
Best ResponseYou've already chosen the best response.0oh.. so (2,5) and (6, 15) First find slope. (m) (y2y1)/(x2x1) x2 x1 = 6  (2) so it becomes 6 + 2 m=(155)/(6+2) m=20/8 is the slope now replace x and y terms (y = mx+b) 5=20/8*2+b?

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0so the slope is 20/8 = 5/2 using one of the given points, (x1, y1) and (x,y) yy1 = 5/2(xx1)

Nick88888888
 one year ago
Best ResponseYou've already chosen the best response.0This is how a certain site said to do it :/ (2,5) and (6, 15) First find slope. (m) (y2y1)/(x2x1) x2 x1 = 6  (2) so it becomes 6 + 2 m=(155)/(6+2) m=20/8 is the slope now replace x and y terms (y = mx+b) 5=20/8*2+b? 5=40/8+b 5+40/8=b (40+40)/8=b 80/8=b the y intercept Thus equation being y=20x/8+80/8

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0@Nick88888888 you don't need a site to tell you to always reduce to the lowest term

butterflydreamer
 one year ago
Best ResponseYou've already chosen the best response.2hmm... not quite. First you want to find the slope (m) So, use the formula: dw:1435467038575:dw Then you want to use the formula: y = mx + b (this is your pointintercept formula) Use (2, 5) where (x,y) therefore x = 3, y = 5 and we know m(slope) = 20/8 Therefore: \[y=mx + b \rightarrow 5= 20/8 \times2 +b \] From here, multiply everything by 8 to get rid of the fraction: 5*8 = 20(2) + 8b 40 = 40 + 8b Subtract 40 from both sides, 40  40 = 40 + 8b  40 0 = 8b Find the value of b by dividing both sides by 8 and we get b = 0 Then plug this into your formula: y= mx + b , where we now know the value of m and b :)

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0k the m is 20/8 so we just need the other formula \[yy_{1}=\frac{5}{2}(xx_1)\]

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0@Nick from your post above "now replace x and y terms (y = mx+b) 5=20/8*2+b?" the process is correct but you made a mistake x is 2 you used 2

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0you need to distribute the negative because x_1 = 2 \[y5=\frac{5}{2}(x+2))\]

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0I got 5/2 because 20/8 can be reduced further... divide both of them by 4

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0then you have to distribute that 5/2 to x and 5/2 to 2 afterwards add 5 to both sides.
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