integrate 1/x^1.005

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integrate 1/x^1.005

Mathematics
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first write is as x ^ n
using 1 / x^m = x^-m
yes, x^-1.005. is this right?

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good, so you have to integrate it now, (with respect to x, i'm assuming) \[\int x^{-1.005}\,\mathrm dx\] are you given limits or not?
yes dx and also i am given the limits, but i am wondering on how to integrate that first.
the limits arent necessary at this moment, am i correct? or is it?
the general case is \[\int x^n\,\mathrm dx = \frac{x^{n+1}}{n+1}+c\] for the indefinite integral and \[\int\limits_{x_i}^{x_f} x^n\,\mathrm dx = \left.\frac{x^{n+1}}{n+1}\right|_{x=x_i}^{x=x_f}\] for the definite integral
i remember it as: "add one to the index, and divide by the new index"
so the integration is the same before substituting the values of limits right?
yeah, pretty much
yeah, that's what i did, but in the solution i have here, it says its integral is -(200/x^0.005)
im confused by the 200
what did you get?
my answer is x^0.005/0.005
what is 1/0.005 equal to?
oh wait, is it because 0.005 is 1/200?
yes!
i just entered on the calcu. lol
yeah im having second thoughts lol. maybe the solution made the x the denominator again?
but now im confused where the negative came from. the answer is -(200/x^0.005)
x^(-1.005) x^(-0.005) / -0.005 = -200 x^(-0.005) = -200 / x^(0.005)
oh yes of course i forgot its -0.005 not 0.005. haha. hey thanks man, appreciate the help
if this is the indefinite integral (no limits) don't forget to +c
yup thanks again!

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